All categories

2 years ago

Find the Diameter of the Circle with the following equation. Round to the nearest tenth.

Mathematics

1 answer:

Radda [10]2 years ago

3 0

The diameter of the circle is 11.8 units

<h3>How to determine the diameter of the circle?</h3>

The circle equation is given as:

(x - 2)^2 + (y + 6)^2 = 35

A circle equation is represented as:

(x - a)^2 + (y - b)^2 = r^2

Where

Diameter = 2r

By comparing both equations, we have

r^2 = 35

Take the square root of both sides

r = 5.9

Multiply by 2

2r = 11.8

Hence, the diameter of the circle is 11.8 units

You might be interested in

1. Your annual salary is $73, 300 and get paid bi-weekly. You are married and

r-ruslan [8.4K]

Fnfnf kenzie said i had trttttttttt

3 0

3 years ago

What is the value of d to the nearest tenth?

Ghella [55]

Answer: $d=13.8$

Step-by-step explanation:

A line that cuts a circle at two points is called "secant".

There is a theorem known as "Intersecting Secant Theorem". This is the theorem you need to use to find the value of "d".

According the Intersecting Secant Theorem:

$(14)(14+20)=(16)(16+d)\\(14)(34)=(16)(16+d)$

Having this expression, the next step is to solve for "d":

Use Distributive property:

$476=256+16d$

Subtract 256 from both sides:

$476-256=-256+256+16d$

$220=16d$

Divide both sides by 16:

$\frac{220}{16}=\frac{16d}{16}\\\\13.75=d$

The value of "d" rounded to the nearest tenth is:

$d=13.8$

6 0

3 years ago

The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c

Anestetic [448]

Answer:

a) The mean is $\mu = 60$

b) The standard deviation is $\sigma = 9$

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when $X = 55.5, Z = -0.5$