Question

Last Sunday, the average temperature was 8%, percent higher than the average temperature two Sundays ago. The average temperature two Sundays ago was T
degrees Celsius.
Which of the following expressions could represent the average temperature last Sunday?
Choose 2 answers:
Choose 2 answers:

(Choice A)
A
\left(1+\dfrac{8}{100}\right)T(1+
100
8
​
)Tleft parenthesis, 1, plus, start fraction, 8, divided by, 100, end fraction, right parenthesis, T

(Choice B)
B
T+8T+8T, plus, 8

(Choice C)
C
1.08T1.08T1, point, 08, T

(Choice D)
D
1.8T1.8T1, point, 8, T

(Choice E)
E
T+0.08T+0.08

Answer 1

Answer:

A. $\left(1+\dfrac{8}{100}\right)T$

C. $1.08T$

Step-by-step explanation:

Given:

Average temperature two Sundays ago was 'T' degree Celsius.

The average temperature for the last Sunday was 8% higher than the average temperature two Sundays ago.

Therefore, the average temperature last Sunday is given as:

$=T+8\%\ of\ T\\\\=T+\dfrac{8}{100}\times T..............(\textrm{Converting percent to fraction by dividing by 100})\\\\=T+\dfrac{8T}{100}\\\\=\left(1+\dfrac{8}{100}\right)T(Choice\ A).............(\textrm{Factoring T out})\\\\=\left(1+0.08\right)T...............(\because \frac{8}{100}=0.08)\\\\=1.08T(Choice\ C)$

Therefore, the correct choices are A and C.

Answer 2

Answer:

C&B

Step-by-step explanation:

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