Answer:
- translate down 3
- reflect across the horizontal line through A
Step-by-step explanation:
1. There are many transformations that will map a line to a parallel line. Translation either horizontally or vertically will do it. Reflection across a line halfway between them will do it, as will rotation 180° about any point on that midline.
In the first attachment, we have elected to translate the line down 3 units.
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2. Again, there are many transformations that could be used. Easiest is one that has point A as an invariant point, such as rotation CW or CCW about A, or reflection horizontally or vertically across a line through A.
Any center of rotation on a horizontal or vertical line through A can also be used for a rotation that maps one line to the other.
In the second attachment, we have elected to reflect the line across a horizontal line through A.
It’d be 2=-2 ... but then subtract two from both side and the answer is a null set. Also known as “no solution”..
Best of luck in your studies :)
-Nicky
Hey there!
⇒ Use the vertex as the middle letter, and the point from each side (<ABC or <CBA)
⇒ Use the vertex only (<B)
⇒ Use a number (<1)
- Classify angles according to their measure.
⇒ Acute angle: less than 90°
⇒ Right angle: exactly 90°
⇒ Obtuse angle: between 90° and 180°
⇒ Straight angle: exactly 180°
Thank you,
Eddie
See the attachment for a visual!
Point slope equation for point (h,k) and slope m is given by
y-k=m(x-h)
compare given equation with formula
we get h=-7, k=3
so the required point is (-7,3)
Thank you for posting your question here. I hope the answer below will help.
Vo=110 feet per second
<span>ho=2 feet </span>
<span>So, h(t) = -16t^2 +110t +2 </span>
<span>Take the derivative: h'(t) = 110 -32t </span>
<span>The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0. </span>
<span>So, set h'(t)=0 and solve for t: </span>
<span>0 = 110 -32t </span>
<span>-110 = -32t </span>
<span>t=3.4375 </span>
<span>t=3.44 seconds </span>
