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3 years ago

Write the expression i35 in the standard form

Mathematics

1 answer:

Sveta_85 [38]3 years ago

6 0

I'm sorry if I'm wrong but I think the answer is -31
No wait nvm maybe not I'm so sorry I can't remember

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Answer? ............

Ksju [112]

X = 36
because angle 108 = 3x
3 x 36 = 108

hope it makes sense, if you have any questions let me know

3 0

2 years ago

Read 2 more answers

Akira recives a prize at a science fair for having the most information project her trophy is in the shape of a square pyramid a

liberstina [14]

Answer:

Step-by-step explanation:

Because I think it is

4 0

2 years ago

Solve each linear equation for x. (A) –12x + 9 = –15x x = (B) 4.5x + 11.5 = 8.5x + 3.5 x = (C) 23x – 9 = 13x x =

mojhsa [17]

Answer:

A. x = -3

B. x = 2

C. x = 9/10

Step-by-step explanation:

(A) –12x + 9 = –15x

Collect like terms

9 = -15x + 12x

9 = -3x

x = 9 / -3

x = -3

(B) 4.5x + 11.5 = 8.5x + 3.5

4.5x - 8.5x = 3.5 - 11.5

-4x = -8

x = -8 / -4

x = 2

-9 = 13x - 23x

-9 = -10x

x = -9 / -10

x = 9/10

5 0

2 years ago

Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin

jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

GIVEN :-

There are 2 right-angled triangles.

In the triangle on the right side ,

Hypotenuse = 26m
Base = 10m

In the triangle on the left side ,

Base = 18m

TO FIND :-

Length of the common perpendicular to both triangles.
Length of the hypotenuse of the triangle on the left side.

FACTS TO KNOW BEFORE SOLVING :-

$Hypotenuse = \sqrt{Base^2 + Perpendicular^2}$ .
$Perpendicular = \sqrt{Hypotenuse^2 - Base^2}$

SOLUTION :-

In the triangle on the right side ,

$Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m$

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

$Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m$

∴ x = 30m

3 0

3 years ago

Write an equation of the line that passes through (2,−5) and is parallel to the line 2y=3x+10.

r-ruslan [8.4K]

Step-by-step explanation:

the eqn is 3x-2y+10=0

slope m=-3/-2=3/2 (m=(-xcoeff/ycoeff)

eqn is

y-y1=m(x-x1)

y+5=3/2(x-2)

2y+10=3x-6

3x-2y-16=0

8 0

3 years ago