Answer:
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
z1 = (70-71)/4 = -0.25
z2 = (72-71/4 = 0.25
P(70<X<72) = p(-0.25<z<0.25) = 0.1974
Answer: 0.1974
(b) If a random sample of thirteen 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
z1 = (70-71)/(4/sqrt(13)) = -0.9014
z2 = (72-71/(4/sqrt(13)) = 0.9014
P(70<X<72) = p(-0.9014<z<0.9014) = 0.6326
Answer: 0.6326
please mark me the brainiest
Answer:
a line segment because it never said anything about a curve
39 students have a pet because 130 times .30 which represents thirty percent gives you the answer
Answer:
11
Step-by-step explanation:
33÷11=3
22÷11=2
3 and 2 habe no common factors
We have to see how many times 130 fits into 1494.23:
So now we have to multiply this by the amount of time needed for 130 meters:
11.4940*1=11.4940.
So the answer is 11.4940 minutes.
