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sleet_krkn [62]
3 years ago
12

Gina started with the circle (x−2)2+y2=16. She translated it 4 units left and 1 unit down. Then she reduced the radius by 1 unit

. What is the equation of her new circle?
Mathematics
1 answer:
olchik [2.2K]3 years ago
5 0

Answer:

(x + 2)² + (y + 1)² = 9

Step-by-step explanation:

Gina started with a circle with the given equation as,

(x - 2)² + (y - 0)² = 16

Since, standard equation of a circle is,

(x - a)² + (y - b)² = r²

Here (a, b) is the center of the circle and 'r' is the radius.

Therefore, from the given equation of the circle,

Center of the circle → (2, 0)

Radius of the circle → √16 = 4 units

She translated this circle 4 units left and 1 unit down.

Rule for the new center after translation will be,

(x, y) → (x - 4, y - 1)

(2, 0) → (2 - 4, 0 - 1)

         → (-2, -1)

Coordinates of the new center → (-2, -1)

Then she reduced the radius by 1 units.

Therefore, radius of the new circle = 4 - 1 = 3 units

Now we substitute these values in the standard equation of the circle to get the equation of the new circle.

(x + 2)² + (y + 1)² = 3²

(x + 2)² + (y + 1)² = 9

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Answer:

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Step-by-step explanation:

Given:

Diameter of the center = 5 inches

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We need to find the part of the center to the whole target.

Solution,

Firstly we will find out the areas of center and whole target.

For center;

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radius = \frac{diameter}{2}=\frac{5}{2}=2.5\ in

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

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radius = \frac{diameter}{2}=\frac{25}{2}=12.5\ in

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framing in equation form, we get;

Area = \pi \times12.5^2

Now to find the part of the center to the whole target we will divide Area of center with Area of the target.

framing in equation form we get;

the part of the center to the whole target = \frac{\pi \times2.5^2}{\pi \times12.5^2}= \frac{6.25}{156.25} = \frac{1}{25}

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6 0
3 years ago
X+y=2 8x+3y=-19 substitution
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Answer:

{x,y}={−5,−7}

Explain:

// Solve equation [2] for the variable  y [2]    3y = 7x + 14 [2]    y = 7x/3 + 14/3 // Plug this in for variable  y  in equation [1] [1]    8x - 3•(7x/3+14/3) = -19 [1]    x = -5 // Solve equation [1] for the variable  x [1]    x = - 5 // By now we know this much : x = -5 y = 7x/3+14/3 // Use the  x  value to solve for  y y = (7/3)(-5)+14/3 = -7 Solution : {x,y} = {-5,-7}

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