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3 years ago

Periaqueductal gray neurons send descending axons into various regions of the medulla releasing serotonin.

Biology

1 answer:

Evgesh-ka [11]3 years ago

5 0

Answer:

True

Explanation:

Periaqueductal gray matter is found in the middle portion of brain. When this grey matter is stimulated it activates neurons that releases enkephalin. Enkephalin further direct the stimulation to the raphe nuclei with in the brain stem that releases serotonin. In this process, the ascending and descending axons are released from

a) subcortical nuclei

b) spinal trigeminal nuclei

c) the spinal cord

Hence, the given statement is true

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Answer:

the steps are

we need to keep tight security system in forest area

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3 years ago

This type of consistent adaptation between two species is known as

Maurinko [17]

Answer:

Symbiosis or Mutualism: When two species live together in a close association that is helpful to both species, the relationship is known as symbiosis. The oxpecker bird and the rhinoceros exhibit this relationship. The oxpecker receives protection and obtains food from the ticks and other pests infesting the rhino’s skin.

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3 years ago

Mom is A+. She has 2 children, one is O+ and the other is B-. (Note: Rh+ is RR or Rr, and Rh- is rr) What are the father’s possi

mezya [45]

Answer:

The blood group of the father must be B.
The genotype of blood group would be $I^{B}i$ .
The Rh factor of the father can either be positive or negative.
Thus, the genotype of Rh factor of father would be either Rr or rr.

Rh factor:

The phenotype of the mother Rh factor is positive. Thus, she can have Rr or RR as her genotype as positive is a dominant trait.

If the genotype of the mother is RR then all the offspring would be positive for Rh factor. However, one of the offspring is Rh negative, that means the mother must be heterozygous that is, Rr.

The genotype of the father can either be Rr or rr in order to produce offspring with positive as well as negative Rh.

Blood group:

The blood group of the mother is A. Thus, the genotype can either be $I^{A}I^{A}$ or $I^{A}i$ .

However, the blood groups of the children are O+ and B+.

Thus, the genotype of the mother must be heterozygous that is $I^{A}i$ .

The blood group of the father must be B with genotype $I^{B}i$ in order to produce offspring with blood group O and B.

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3 years ago