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Novay_Z [31]
2 years ago
5

An aerospace company has submitted bids on two separate federal government defense contracts. The company president believes tha

t there is a 40% probability of winning the first contract. If they win the first contract, the probability of winning the second is 72%. However, if they lose the first contract, the president thinks that the probability of winning the second contract decreases to 54%.A. What is the probability that they win both contracts?Probability =B. What is the probability that they lose both contracts?Probability =C. What is the probability that they win only one contract?Probability =
Mathematics
1 answer:
gulaghasi [49]2 years ago
7 0

Answer:

1)28.8%

2)28.8%

3)43.6%

Step-by-step explanation:

1))Probability of wining both = Probability that first contract is won* Probability that second contract is won = 0.4 * 0.72 = 0.288 = 28.8%

2)Probability of losing = 1 - Probability of winning

Probability that they will lose both contracts = Probability that first contract is lost * Probability that second contract is lost = (1 - 40/100) * (1 - 54/100) = 0.276 = 27.6%

3)Probability that any one is won = 1 - both contracts are won - both contracts are lost = 1 - 0.276 - 0.288 = 0.436 = 43.6%

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The hexagon GIKMPR is regular. The dashed line segments form 30 degree angles.
Gwar [14]

Answer:

The correct option is (D).

Step-by-step explanation:

It is given that GIKMPR is regular hexagon. It means it has 6 vertices.

Since the central angle is 360 degree. Therefore the central angle between two consecutive vertices is

\frac{360^{\circ} }{6}=60^{\circ}

It is given that the dashed line segments form 30 degree angles.

We have rotated the hexagon about O to map PQ to RF. Since P and R are consecutive vertices, therefore the angle between them is 60 degree.

The vertex R is immediate next to the vertex P in clockwise direction.

So if we rotate the hexagon at 60 degree clockwise about O, then we can maps PQ to RF.

360^{\circ}-60^{\circ}=300^{\circ}

Therefore we can also rotate the hexagon at 300 degree counterclockwise about O, then we can maps PQ to RF.

Therefore option D is correct.


8 0
3 years ago
Convert vector B= 12i+5j to polar coordinates
Dmitriy789 [7]
THE ANSWER WILL BE 3 BECAUSE I HAD DID MY MATH

7 0
2 years ago
Need number 6.) <br> With answer and graphing chart included!
Aloiza [94]
#4 is B, #5 is A, and #6 is C
6 0
3 years ago
Evelyn's made a cake in the shape of a circus tent the cake consisted of a cylinder and a cone .The height of the cone is half t
Lera25 [3.4K]
The volume of the cake is 1470 in³. 
volume of a cylinder = πr² x height
(Think about how a cylinder is basically a bunch of circles stacked on top of each other. To find the volume, first you need the area of the circle (πr², then you multiply by how many circles you are stacking on top of each other (height)) 

we know the diameter of the cylinder is 12 in. and the radius is half of the diameter. 
half of 12 is 6, therefore the radius is 6 in. or r = 6 
Assuming pi is 3.14, solve for the height of the cylinder
1470 = (3.14)(6²)(height)
1470 = 3.14 x 36 x height
1470 = 113.04 x height
height ≈ 13 in

Now that we know the height of the cylinder is about 13 in., we know the height of the cone, because the problem says that the height of the cone is half the height of the cylinder. 
half of 13 is 6.5, therefore the height of the cone is 6.5 
the radius of the cone is the same as that of the cylinder, 6 in. 

volume of a cone = πr² × (height ÷ 3)

volume of the cone = (3.14)(6²)(6.5 ÷ 3)
volume of the cone = (3.14)(36)(2.16666)
volume of the cone = 244.92 in³

Now all that's left to find the volume of the whole cake is to add the volume of the cylinder to the volume of the cone. 

1470 + 244.92 = 1714.92 in³



6 0
3 years ago
(-1,-2) rotation 180 about the origin
mylen [45]

Answer:

(1,2)

Step-by-step explanation:

The rule to rotate any coordinate around the origin is

x,y -->  -x,-y

-1,-2 would become 1,2

4 0
3 years ago
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