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3 years ago

Find the arc length of the partial circle.

Mathematics

2 answers:

pogonyaev3 years ago

8 0

Answer:

Step-by-step explanation:

A full circle has a circumference of 2*pi * r

r = 1

so Full Circle = 2 * PI

1/4 Circle = 2*pi / 4 = 1/2 pi

The length of the arc length = 1/2 pi

Just in case you prefer the more numerical answer, 1/2 * 3.14 = 1.57

nalin [4]3 years ago

7 0

Answer:

1/2 pi

Step-by-step explanation:

This is 1/4 of a circle

Find the circumference and multiply by 1/4

1/4 C

1/4 ( 2*pi*r) where r is the radius

The radius is 1

1/2 pi*1

1/2 pi

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What function is graphed below?

lidiya [134]

Answer: y = 2x^4

The graph represents a parabolic-looking shape so it's either a quadratic or some even degree polynomial. This rules out y = -2x^3 and y = 2x^3 as they are cubics with odd degrees

The degree of a polynomial is the largest exponent. It determines the end behavior. In this case, both ends are rising upward together. Because they are rising up in the positive y direction, this means that we cannot have y = -2x^4 as the answer. For example, if x = 2 then y = -2*x^4 = -2*2^4 = -32, but the point (x,y) = (2,-32) isn't on the blue curve. So we can rule y = -2x^4 out.

The fact that y = 2x^4 has a positive leading coefficient tells us that the endpoints point upward.

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2 years ago

Reduce your fraction into lowest terms.<br><br>

neonofarm [45]

21/35= 3/5 this is the lowest fraction

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2 years ago

Find the probability that the person is frequently or occasionally involved in charity work.

Schach [20]

Given the table below which shows the result of a survey that asked 2,881 people whether they are involved in any type of charity work.

$\begin{tabular}
{|c|c|c|c|c|c|}
 &Frequently&Occassionally&Not at all&Total\\[1ex]
Male&227&454&798&1,479\\
Female &205&450&747&1,402\\
Total&432&904&1,545&2,881
\end{tabular}$

Part A:

If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

$P(being \ frequently \ involved \ or \ being \ occassionally \ involved)\\ \\= \frac{432}{2881} + \frac{904}{2881} = \frac{1336}{2881}=\bold{0.464}$

Part B:

If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

$P(being
 \ female \ or \ not \ being \ involved)\\ \\= 
\frac{1402}{2881} + \frac{1545}{2881}-\frac{747}{2881} = 
\frac{2200}{2881}=\bold{0.764}$

Part C:

If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

$P(being
 \ male \ or \ being \ frequently \ involved)\\ \\= 
\frac{1479}{2881} + \frac{432}{2881}-\frac{227}{2881} = 
\frac{1684}{2881}=\bold{0.585}$

Part D:

If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

$P(being
 \ female \ or \ not \ being \ frequently \ involved)\\ \\= 
\frac{1402}{2881} + \frac{904}{2881} + \frac{1545}{2881}-\frac{450}{2881}-\frac{747}{2881} = 
\frac{2654}{2881}=\bold{0.921}$

Part E:

The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.

Indeed from the table, there are 205 females who are frequently involved in charity work.

Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".

4 0

2 years ago

What is the solution of the equation 1.6m - 4.8 = -1.6m

Flauer [41]

Solve for m:
1.6 m - 4.8 = -1.6 m

Add 1.6 m to both sides:
1.6 m + 1.6 m - 4.8 = 1.6 m - 1.6 m

1.6 m - 1.6 m = 0:
1.6 m + 1.6 m - 4.8 = 0

1.6 m + 1.6 m = 3.2 m:
3.2 m - 4.8 = 0

Add 4.8 to both sides:
3.2 m + (-4.8 + 4.8) = 4.8

4.8 - 4.8 = 0:
3.2 m = 4.8

Divide both sides of 3.2 m = 4.8 by 3.2:
(3.2 m)/3.2 = 4.8/3.2

3.2/3.2 = 1:
m = 4.8/3.2

4.8/3.2 ≈ 1.5:
Answer: m ≈ 1.5

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3 years ago

A factory makes light fixtures with right regular hexagonal prisms where the edge of a hexagonal base measures 4 cm and the leng

chubhunter [2.5K]

The maximum length of the prism is highest length of the hexagonal prism

The maximum length of each prism is 8.0 cm

<h3>How to determine the maximum length of each prism?</h3>

The surface area of the hexagonal prism is calculated using:

A = 6al + 3 $\sqrt$ 3 a^2

Where:

a represents the edge length; a = 4 cm

l represents the length (or height) of the prism

The surface area costs $0.04 per square centimeter.

So, we have:

C = 0.04 * [6al + 3 $\sqrt$ 3 a^2]

The maximum cost is $11.

So, the equation becomes

11 = 0.04 * [6al + 3 $\sqrt$ 3 a^2]

Substitute 4 for a

11 = 0.04 * [6 * 4l + 3 $\sqrt$ 3 * 4^2]

Evaluate the products and exponents

11 = 0.04 * [24l + 48 $\sqrt$ 3]

Divide both sides by 0.04

275 = 24l + 48 $\sqrt$ 3

Subtract 48 $\sqrt$ 3 from both sides

24l = 275 - 48 $\sqrt$ 3

Evaluate the difference

24l = 191.9

Divide both sides by 24

l = 8.0

Hence, the maximum length of each prism is 8.0 cm