Answer:
Genotypic ratio = 16 WwDd: 0
Phenotypic ratio = 16 white, disk shaped fruit : 0 yellow, sphere shaped fruit
Explanation:
This question involves two different genes coding for fruit color and fruit shape respectively. The allele for white fruit color (W) is dominant over yellow fruit color (w) and disk shaped fruit (D) is dominant over sphere-shaped fruit (d).
According to this question, If a squash plant pure-breeding for white, disk shaped fruit (WWDD) is crossed with a plant pure breeding for yellow, sphere shaped fruit (wwdd), the following gametes will be produced by each GAMETE:
WWDD - WD, WD, WD, WD
wwdd - wd, wd, wd, wd
Using these gametes in a punnet square, all of the offsprings will have genotype WwDd, which is phenotypically white and disk shaped fruit.
The genotypic ratio is 4 WwDd: 0
The phenotypic ratio is 16 white, disk shaped fruit : 0 yellow, sphere shaped fruit.
Answer:
Barr bodies are small bodies that are dark staining bodies that show the inactivated X chromosome, these sex chromatin bodies attach to the membrane of the nucleus of interphase cells.
One less of the total number of X-chromosome (n-1) represents the number of Barr bodies.
Then,
The number of Barr bodies with Klinefelter would be:
Klinefelter (47,XXY): (n-1) = (2-1) = 1 Barr body as here two X chromosome present.
Similarly, for
Turner (45,XO): (n-1) = (1-1) = 0 Barr bodies (X chromosome = 1)
Now, as per the question, the bar bodies for karyotypes given
47,XYY: (n-1) = (1-1) = 0 Barr bodies
47,XXX: (n-1) = (3-1) = 2 Barr bodies
48,XXXX: (n-1) = (4-1) = 3 Barr bodies
Dominant allele frequency (p) :0.98
Hope this helps.