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LUCKY_DIMON [66]
2 years ago
12

PLEASEEE HELP IMEDDIATLYYY I WILL GIVE BRAINLIEST PLEASEEEEEEEEE

Biology
1 answer:
Levart [38]2 years ago
8 0
The third one is the first and the 5th one is the second and the 1st one is the last
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The systolic arterial blood pressure observed for 20 dogs is normally distributed with a mean of 152 mm of mercury (hg) and a st
Damm [24]

Given: The systolic arterial blood pressure observed for 20 dogs is normally distributed with a mean of 152 mm of mercury (Hg) and a standard deviation of 18 mm of Hg.  

To find: P(100 < 152)

Method: Calculation of Z-Score followed by the probability or area of the bell curve at X = 100.

Solution:

Mean u = 152, std s = 18

Z score = \frac{X-u}{s} = \frac{100-152}{18} = -2.89

The value of P(100<152) is calculated by looking at the value of Z in the Z score for the standard normal distribution given in the image.

P(Z=-2.89) = 0.0019

The P(Z = -2.89) corresponds to the area in the left tail of the bell curve.

Thus the probability of 100 mm Hg blood pressure is 0.0019.

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3 years ago
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