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mariarad [96]
3 years ago
15

For a class of 25 students, 5 pizzas are needed for

Mathematics
1 answer:
Darina [25.2K]3 years ago
5 0

Answer:

80

Step-by-step explanation:

25:5=400:x

×=(400×5):25

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I need help with questions #7 and #8 plz
katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

c^2 = a^2 + b^2 - 2ab \cos C

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

18^2 = 12^2 + 16^2 - 2(12)(16) \cos C

324 = 144 + 256 - 384 \cos C

-384 \cos C = -76

\cos C = 0.2

C = \cos^{-1} 0.2

C = 78.6^\circ

Now we use the law of sines to find angle A.

Law of Sines

\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}

We know c and C. We can solve for a.

\dfrac{a}{\sin A} = \dfrac{c}{\sin C}

\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}

Cross multiply.

18 \sin A = 12 \sin 78.6^\circ

\sin A = \dfrac{12 \sin 78.6^\circ}{18}

\sin A = 0.6535

A = \sin^{-1} 0.6535

A = 40.8^\circ

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

a^2 = b^2 + c^2 - 2bc \cos A

b^2 = a^2 + c^2 - 2ac \cos B

c^2 = a^2 + b^2 - 2ab \cos C

Find angle A:

a^2 = b^2 + c^2 - 2bc \cos A

8^2 = 18^2 + 12^2 - 2(18)(12) \cos A

64 = 468 - 432 \cos A

\cos A = 0.9352

A = 20.7^\circ

Find angle B:

b^2 = a^2 + c^2 - 2ac \cos B

18^2 = 8^2 + 12^2 - 2(8)(12) \cos B

324 = 208 - 192 \cos A

\cos B = -0.6042

B = 127.2^\circ

Find angle C:

c^2 = a^2 + b^2 - 2ab \cos C

12^2 = 8^2 + 18^2 - 2(8)(18) \cos B

144 = 388 - 288 \cos A

\cos C = 0.8472

C = 32.1^\circ

8 0
3 years ago
I’ve tried to work this out but I can’t get it figured out. Can someone help me
Bas_tet [7]
G(2) = -4(2) = -8
f(g(2)) = (-8)^2 = 64

answer 
64
5 0
3 years ago
Please I need help is the answer is C
NemiM [27]
It’s d because 2x4x8 = 64
8 0
3 years ago
A girl ran from her home to a store at the rate of 6 mph, and she walked back home at the rate of 4 mph. if it took 15 minutes f
viva [34]

Home is 0.6 miles away from the store

How to solve such time related questions?

The key concept for solving such questions is the relationship between speed, distance and time.

The relationship between them is Distance = Speed x Time

Given:-

Total time taken by girl to complete the trip = 15 minutes = \frac{1}{4} hours

Speed while riding going = 6 miles per hour

Speed while coming back = 4 miles per hour

Total time taken by girl  =

Time taken while going +   Time taken while coming back      - (1)

  Let x be distance from home to store

       \frac{x}{6} =  Time taken while going

\frac{x}{4} = Time taken while coming back

    Substituting in (1) we get

      \frac{1}{4} =  \frac{x}{6} + \frac{x}{4}

      \frac{1}{4} =  \frac{2x + 3x}{12}

       \frac{1}{4} =  \frac{5x}{12}

      x= \frac{12}{20}

    x = 0.6 miles

Thus home is 0.6 miles away from the store

Learn more about time related  here :

brainly.com/question/12759408

#SPJ4

6 0
2 years ago
Fill in the blank to this mathematics question
lorasvet [3.4K]

Answer:

x = 24 makes the original equation true

Step-by-step explanation:

2 < x ≤ 24

2 < x signifies x cannot be equal to 2

x≤24 signifies x can be equal to 24.

3 0
3 years ago
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