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Vinvika [58]
3 years ago
14

Darla budgeted $150 per week for food. Her actual monthly amount was an average of $700. Did Darla budget correctly?

Mathematics
1 answer:
mote1985 [20]3 years ago
6 0
Yes she did :):):):):):)
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Ruth is knitting hats to sell at a local fair. The booth costs her $63 and the materials for each hat cost $10. She plans on sel
aev [14]

Answer: Ruth have to make 7 hats to break even.

Step-by-step explanation:

Break even point is a point where Cost = Revenue.

Let x be the number of hats sold.

Given: Cost of booth = $63

Each hat cost = $10

Selling price for each cost = $19

As per given,

Total cost = Cost of booth+ (Cost of each hat)(Number of hats)

= 63+10x

Total selling price = 19x

For break even,

63+10x=19x

9x=63

x=7

Hence, Ruth have to make 7 hats to break even.

7 0
3 years ago
What is √18x^6 written in simplest for? assume all variables are positive.
Nadya [2.5K]

Your answer should be C. 3x^3√2

3 0
3 years ago
Suppose a local manufacturing company claims their production line has a variance of less than 9.0. A quality control engineer d
Alexxx [7]

Answer:

\chi^2 =\frac{35-1}{9} 2.12^2 =16.979

p_v =P(\chi^2

If we compare the p value and the significance level provided we see that p_v so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=35 represent the sample size

\alpha=0.01 represent the confidence level  

s =2.12 represent the sample deviation obtained

\sigma_0 =3 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 9 and the deviation lower than 3, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 9

Alternative hypothesis: \sigma^2

Calculate the statistic  

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{35-1}{9} 2.12^2 =16.979

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case df= n-1= 35-1=34. And since is a left tailed test the p value would be given by:

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(16.979,34,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

6 0
3 years ago
Identify the degree of the polynomial. 4x4 – 3x2 + 7x – 11
Romashka [77]

Answer:  x=7x−1

Step-by-step explanation:

7 0
3 years ago
How many families in Oats Township have two or more cars?<br> 100<br> 4<br> 1<br> 2<br> 400<br> 200
Colt1911 [192]

Answer:

200

Step-by-step explanation:

Good luck <3

5 0
3 years ago
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