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Dmitriy789 [7]
3 years ago
14

If f(x) = x + 5, what does f(8) represent? (1 point) Group of answer choices The value of x when (x + 5) = 8 The value of 8f(x)

when x = 8 The value of f(x) when (x + 5) = 8 The value of (x + 5) when x = 8
Mathematics
1 answer:
baherus [9]3 years ago
3 0

Answer:

a

Step-by-step explanation: thank me later

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Determine whether −6x+y=−1 is a function.
kenny6666 [7]

Answer:

 is a function

Step-by-step explanation:

Any linear relation involving both x and y is a function.

__

<em>Additional comment</em>

A line of the form x=constant is the only sort of line that is not a function. As you can see, it does not involve y, which is why I put the restriction in the above statement.

7 0
3 years ago
1
Papessa [141]

Answer:

d = 10/72

Step-by-step explanation:

c and d vary inversely

c = k/d

Where,

k = constant of proportionality

d = 2/9 when c = 5

c = k/d

5 = k ÷ 2/9

5 = k × 9/2

5 = 9k/2

Cross product

5*2 = 9k

10 = 9k

k = 10/9

c = k/d

c = 10/9 ÷ d

c = 10/9 × 1/d

c = 10/9d

find d when c = 8

c = 10/9d

8 = 10/9d

Cross product

8*9d = 10

72d = 10

d = 10/72

8 0
3 years ago
If a multiple choice test consists of ​questions, each of which with of which only 1 is​ correct, ​(a) in how many different way
oksian1 [2.3K]

Answer:

Step-by-step explanation:

From the given information.

suppose a multiple choice test consists of 5 questions, each with 4 possible answers of which 1 is correct.:

So, we can now suggest that a person can answer each question in 4 different ways given that there are 5 different questions.

Thus, the  students can check off one answer to each question in 4^5 \ different \  ways

= 4 × 34 × 4 × 4 × 4

= 1024 different ways.

From the 4 possible answers, since 1 will be correct, definitely 3 other answers will be incorrect.

Thus, the number of ways a student can check off one answer to each question and get all the answers wrong is = 3⁵

= 3 × 3 × 3 × 3 × 3

= 243 ways

3 0
3 years ago
Find the common difference of the arithmetic sequence 13, 16, 19,...13,16,19,...
VLD [36.1K]

Answer:

the common difference is plus 3

4 0
3 years ago
Mrs. Stevenson wants to split her class into 4 teams: Team A, Team B, Team C, and Team D. There are 28 students in her class. To
olga_2 [115]
The probability that both of the students are on Team D is about 5.56%

There are 4 teams, so the first person has a 1/4 chance of being on Team D.

However, for the second person, there are only 6 spots left out of 27 to be on Team D.

To find the combined probability, we need to multiply the two fractions.

1/4 times 6/27 = 1/18 or about 5.56%
3 0
3 years ago
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