Answer:
1. value is 0; x-3 is a factor . . . . . . . . . . . . . .third choice
2. evaluates at x = -1; remainder is -11 . . . . first choice
Step-by-step explanation:
Dividing f(x) by (x -a) gives ...
f(x)/(x -a) = g(x) +r/(x -a) . . . . some quotient and a remainder r
If we multiply this expression by (x -a), we see ...
f(x) = (x -a)g(x) +r
so
f(a) = (a -a)g(a) +r . . . . . evaluate the above equation at x=a
f(a) = 0 +r
f(a) = r . . . . . . . . . a statement of the remainder theorem
If r=0, then x-a is a factor of f(x) = (x-a)g(x).
___
1. We have "a" = 3, and f(3) = 0. Therefore (x-3) is a factor.
__
2. We have "a" = -1, and f(-1) = -11. Therefore the remainder from division by (x+1) is -11.
I don't have a lot of experience with chance, but there are 2 odd numbers before 4, 1 and 3, so it would be 2 out of 6 or 33.3 continuing percent.
I believe the answer is 47.
Answer:
19\2
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
Given
V = πr²h ( isolate h by dividing both sides by πr² )
= h
When V = 36π , r = 3 , then
h =
=
= 4 cm