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Tju [1.3M]
3 years ago
10

12 minus b=-2 solve for b

Mathematics
2 answers:
ycow [4]3 years ago
5 0
12 - b = -2
12 + 2 = b
14 = b
Vika [28.1K]3 years ago
5 0

Answer:

\:  \:  \:  \:  \: \: 12 - b =  - 2 \\  =  >  - b =  - 2 - 12 \\  =  >  -  b =  - 14 \\   =  >  b = 14

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Subtract. (5x2−3x−2)−(−2x2−x+10) Express the answer in standard form. Enter your answer in the box.
Nimfa-mama [501]

Answer:

7x^{2}-2x-12=0

Step-by-step explanation:

we know that

The standard form of the quadratic equation is equal to ax^{2} +bx+c=0

we have

(5x^{2}-3x-2)-(-2x^{2}-x+10)

eliminate the parenthesis

5x^{2}-3x-2+2x^{2}+x-10

group terms that contain the same variable

(5x^{2}+2x^{2})+(-3x+x)+(-2-10)

combine like terms

7x^{2}-2x-12=0

5 0
3 years ago
Read 2 more answers
Solve for x. 5(x – 10) = 30 – 15x
klio [65]
You can start by distributing the 5 to everything in the parenthesis.
5x-50=30-15x

Then get rid of your x values from one side, I chose to subtract 5x

-50 = 30 - 20x

Then subtract 30

-80=-20x
/-20
4=x

You can check by plugging your x into the equation to make sure it's right!

6 0
3 years ago
What is the difference between a copay and coinsurance?
bearhunter [10]

Answer:

A deductible is the amount you pay for a service before the plan shares the cost of the service with you. A copay is a set amount you pay for the service. Coinsurance is when you pay a percentage of the cost for an item or service.

4 0
3 years ago
Explain, with a test, why the two triangles in each figure are similar. Find the
frutty [35]

Answer:

x = 3, y = 6

Step-by-step explanation:

In the figure attached,

If ΔADE and ΔABC are similar triangles, their corresponding sides will be in the same ratio.

By this property,

\frac{AB}{AD}=\frac{AC}{AE}=\frac{BC}{DE}

\frac{AB}{AD}=\frac{AC}{AE}

\frac{AD+BD}{AD}=\frac{AE+EC}{AE}

\frac{3}{2}=\frac{x+1.5}{x}

3x = 2x + 3

3x - 2x = 3

x = 3

Similarly, \frac{AB}{AD}=\frac{BC}{DE}

\frac{3}{2}=\frac{y}{4}

y = \frac{3\times 4}{2}

y = 6

7 0
3 years ago
The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

8 0
3 years ago
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