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Mathematics

2 answers:

laila [671]3 years ago

7 0

33 + 12 would be 45 centimeters square

Illusion [34]3 years ago

3 0

Answer:

45 centimeters squared, or 45cm^2

Step-by-step explanation:

Must find the length and the width of the figure of figures depending on how you decide to do it

Separate the figure into 2 or 3, following the lines given. Say you were to have divided it horizontally, leaving you with 2 figures. One of which has the dimensions 4cm, 3cm, and 4cm on it. The other with the dimensions, 4cm, 3cm, 4cm, and 3 cm on it.
Start with the first figure. The dimensions of Length and Width are already given to you. 4 times 3 gives you 12, meaning the area of the first figure is 12cm^2.
Now the second figure. This one is a tad bit more difficult as it requires you to piece information together. Start with length. We have the dimension 4cm, and on the other side another 4cm, however just above that is a 3cm dimension that completes this side. Together the length of this one is 11 cm. Next, on to the width. This is easy as it is already provided, 3cm. Multiplied by one another, 3cm times 11cm gives us 33cm^2.
Now to add the two figures together. The first figure has a total area of 12cm^2 and the second a total area of 33cm^2. In total, the entire plane has a total area of 45cm^2.

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Ksenya-84 [330]

Answer: Need to clarify more about the question, I dont understand. Sorry ;//

Step-by-step explanation:

3 0

2 years ago

(K3+2k2-82k-28)/(k+10)

Ne4ueva [31]

So for this, we will be using synthetic division. To set it up, have the equation so that the divisor is -10 (since that is the solution of k + 10 = 0) and the dividend are the coefficients. Our equation will look as such:

(Note that synthetic division can only be used when the divisor is a 1st degree binomial)

-10 | 1 + 2 - 82 - 28
---------------------------

Now firstly, drop the 1:

-10 | 1 + 2 - 82 - 28
↓
-------------------------
1

Next, you are going to multiply -10 and 1, and then combine the product with 2.

-10 | 1 + 2 - 82 - 28
↓ - 10
-------------------------
1 - 8

Next, multiply -10 and -8, then combine the product with -82:

-10 | 1 + 2 - 82 - 28
↓ -10 + 80
-------------------------
1 - 8 - 2

Next, multiply -10 and -2, then combine the product with -28:

-10 | 1 + 2 - 82 - 28
↓ -10 + 80 + 20
-------------------------
1 - 8 - 2 - 8

Now, since we know that the degree of the dividend is 3, this means that the degree of the quotient is 2. Using this, the first 3 terms are k^2, k, and the constant, or in this case k² - 8k - 2. Now what about the last coefficient -8? Well this is our remainder, and will be written as -8/(k + 10).

Putting it together, the quotient is $k^2-8k-2-\frac{8}{k+10}$ 