Answer:
see below
Step-by-step explanation:
given: size of television is height = 37 in, length = 71 in.
A. using Pythagorean theorem:
parts given are legs which is the sides
looking for the hypotenuse.
B. formula:
a² + b² = c² or H² + L² = D²
where H = height = 37
L = length = 71
D = diagonal (which is req'd)
C. D² = 37² + 71²
D = 
D = 
D = 80 in (missing length)
D. size of television:
37 x 71 in
Diagonal is 80 in
hope it helps and good luck!
<h2>
Hey Emma Here<em>
!</em></h2>
Answer:
B
Step-by-step explanation:
55.85 divided by 7.25 is 7. something sooooo if pants cost 7 dolars more thats 14
It is D because you would do x+6 and would get y so it represents direct proportion
Supposing a normal distribution, we find that:
The diameter of the smallest tree that is an outlier is of 16.36 inches.
--------------------------------
We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>
<u />
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- The Z-score measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u>
</u>
<u />
In this problem:
- Mean of 8.8 inches, thus
. - Standard deviation of 2.8 inches, thus
.
<u />
The interquartile range(IQR) is the difference between the 75th and the 25th percentile.
<u />
25th percentile:
- X when Z has a p-value of 0.25, so X when Z = -0.675.




75th percentile:
- X when Z has a p-value of 0.75, so X when Z = 0.675.




The IQR is:

What is the diameter, in inches, of the smallest tree that is an outlier?
- The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

The diameter of the smallest tree that is an outlier is of 16.36 inches.
<u />
A similar problem is given at brainly.com/question/15683591