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Blababa [14]
3 years ago
8

Hey Guys . . . I need help again.

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
6 0

Answer:

I believe that the first one is: idk

The second one is : idk

And the last one is: identity property

Step-by-step explanation:

sorry if im wrong

Can you mark me Brainliest

Natalija [7]3 years ago
5 0
1. Associative property (the numbers are grouped different)

2. Commutative property (the numbers are placed different)

3. Identity property
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Helpppppppppppppppp messssss plzzzzzzzzzzzzzzz
elena-14-01-66 [18.8K]

Answer:

1=b

2=f

3=d

4=e

5=a

6=b

So tough question dud

3 0
3 years ago
Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*
dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\

5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\

\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3

7 0
3 years ago
Read 2 more answers
*WILL GIVE BRAINLIEST*
andrey2020 [161]

Answer:

The answer is A.

Step-by-step explanation:

I learned it before.

Hope this helps.

3 0
3 years ago
Read 2 more answers
Brian’s grandmother offered to give him a gift of 50% of the amount of money he saved in one year. His grandmother gave him $60.
Mice21 [21]

Answer:

$120

Step-by-step explanation:

7 0
3 years ago
solve each equation. Round your answers to the nearest ten-thousandth. Show your work please. Part 2A​
Reika [66]

Answer:

16. x = 3.0822, -3.0822

17. x = 1.6432, -1.6432

18. x = 1, -1

Step-by-step explanation:

16. log5[(4x²+2)/8] = 1

(4x²+2)/8 = 5¹

4x² + 2 = 40

4x² = 38

x² = 38/4

x² = 19/2

x = +/- sqrt(19/2)

x = 3.0822, -3.0822

17. log7[(2x²-4)(5)] = 1

10x² - 20 = 7¹

10x² = 27

x² = 2.7

x = +/- sqrt(2.7)

x = 1.6432, -1.6432

18. log5[(2x²+8)/2] = 1

x² + 4 = 5¹

x² = 1

x = +/-1

4 0
3 years ago
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