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sashaice [31]
3 years ago
5

The distance between the school and the airport on a map is 7.25 cm. The scale of the map is 1 cm: 12 m. What is the actual dist

ance between the school and the airport?
Mathematics
1 answer:
pav-90 [236]3 years ago
8 0

Answer:  87m

Step-by-step explanation:

This problem can be solved by using a simple ratio and proportion.

The way you figure this out is:

Model = 12 m/ 1 cm = x/7.25 cm

Solve for x and you should receive this answer:

x = 87 m

Hope I helped :P

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¿que es una division exacta de numeros enteros?
mixas84 [53]

Answer:

La división de dos números enteros es igual al valor absoluto del cociente de los valores absolutos entre el dividendo y el divisor, y tiene de signo, el que se obtiene de la aplicación de la regla de los signos.

8 0
3 years ago
Please help me just wait for me to put the pictures up but this time WAIT
Ganezh [65]
1.A.
The base lengths of the trapezoid are 35cm and 19cm. The height is 15cm.
1.B.
The formula for the area of a trapezoid is
A=(b1+b2)/2*h
plug in the data we know
A=(35+19)/2*15
A=54/2*15
A=27*15
A=405cm²
since there are two trapezoids, we double that number  405*2=810cm²
Answer=810cm²

1.C.
To solve for this, we need to find the perimeter of the trapezoid
P=35+19+17+17=88cm
Answer=No. The edges of the trapezoid are longer than 80cm.

2.A.
3units. Since their x values are the same, you just subtract the y values to calculate distance 5-2=3
Answer=3

2.B
A right triangle. Since one coordinate is directly above, and the other is directly to the right of the bench

3.A
The two triangles would be...
A=1/2b*h=1/2*30*72=15*72=1080ft² each
and the center rectangle would be
A=l*w=20*72=1440ft²
Add them all together and you get
Total area=3600ft²



5 0
3 years ago
The quantity demanded x each month of Russo Espresso Makers is 250 when the unit price p is $138. The quantity demanded each mon
Stells [14]

Answer:

(a)D(q)=\frac{-1}{25} q+148

(b)S(q)=\frac{1}{50}q+58

(c)p_{*} =88\\\\q_{*} =1500

Step-by-step explanation:

(a) For the demand equation D(q) we have

<em>P1: 138 Q1: 250</em>

<em>P2: 108 Q2: 1000</em>

We can find <u><em>m</em></u>, which is the slope of the demand equation,

m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{108-38}{1000-250} =\frac{-30}{750}=\frac{-1}{25}

and then we find b, which is the point where the curve intersects the y axis.

We can do it by plugging one point and the slope into the line equation form:

y=mx+b\\\\D(q)=mq+b\\\\138=\frac{-1}{25}(250) +b\\\\138=-10+b\\\\138+10=b=148

<em>With b: 148 and m: -1/25 we can write our demand equation D(q)</em>

D(q)=\frac{-1}{25} q+148

(b) to find the supply equation S(q) we have

<em>P1: 102 Q1: 2200</em>

<em>P2: 102 Q2: 700</em>

<em></em>

Similarly we find <em>m</em>, and <em>b</em>

m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{72-102}{700-2200} =\frac{-30}{-1500}=\frac{1}{50}

y=mx+b\\\\D(q)=mq+b\\\\72=\frac{1}{50}(700) +b\\\\72=14+b\\\\72-14=b=58\\

<em>And we can write our Supply equation S(q):</em>

S(q)=\frac{1}{50}q+58

(c) Now we may find the equilibrium quantity q* and the equilibrium price p* by writing <em>D(q)=S(q)</em>, which means the demand <u><em>equals</em></u> the supply in equilibrium:

D(q)=S(q)\\\\\frac{-1}{25}q+148=\frac{1}{50}q+58\\\\

148-58=\frac{1q}{50} +\frac{1q}{25} \\\\90= \frac{1q}{50} +\frac{2q}{50}\\\\90=\frac{3q}{50}\\ \\q=1500\\\\

We plug 1500 as q into any equation, in this case S(q) and we get:

S(q)=\frac{1}{50}q+58\\\\S(1500)=\frac{1}{50}(1500)+58\\\\S(1500)=30+58\\\\S(1500)=88

Which is the equilibrium price p*.

8 0
3 years ago
On a fishing trip, Amala caught 54 fish. She released  5/6 <br> of the fish.
Kipish [7]
First turn the fraction to decimal 5/6 <span>0.83333333333333
so 0.83 - 54 is 53.17 fish </span>
8 0
3 years ago
Always solve an algebraic expression by working from the left to right true or false
Gemiola [76]
The answer is FALSE hope this helps
7 0
3 years ago
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