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yawa3891 [41]
3 years ago
13

Help please must show work 1, 2, 3, 4

Mathematics
2 answers:
My name is Ann [436]3 years ago
8 0
Those are the answers for 1-4. Tell me if I should do the others or not.

Levart [38]3 years ago
3 0
The answer to the question

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I need help with internet’s I am not doing good in math and I really need help
sweet [91]

Answer:

Then get some help

5 0
3 years ago
Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14
PilotLPTM [1.2K]

Answer:

<em>Carbon-14 will take 19,035 years to decay to 10 percent.</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.

An exponential decay can be described by the following formula:

N(t)=N_{0}e^{-\lambda t}

Where:

No  = The quantity of the substance that will decay.

N(t) = The quantity that still remains and has not yet decayed after a time t

\lambda     = The decay constant.

One important parameter related to radioactive decay is the half-life:

\displaystyle t_{1/2}=\frac {\ln(2)}{\lambda }

If we know the value of the half-life, we can calculate the decay constant:

\displaystyle \lambda=\frac {\ln(2)}{ t_{1/2}}

Carbon-14 has a half-life of 5,730 years, thus:

\displaystyle \lambda=\frac {\ln(2)}{ 5,730}

\lambda=0.00012097

The equation of the remaining quantity of Carbon-14 is:

N(t)=N_{0}e^{-0.00012097\cdot t}

We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No

0.10N_o=N_{0}e^{-0.00012097\cdot t}

Simplifying:

0.10=e^{-0.00012097\cdot t}

Taking logarithms:

ln 0.10=-0.00012097\cdot t

Solving for t:

\displaystyle t=\frac{log 0.10}{-0.00012097}

t\approx 19,035\ years

Carbon-14 will take 19,035 years to decay to 10 percent.

6 0
3 years ago
Read 2 more answers
Select the two values of x that are roots of this equation.<br>x + 2x - 6 = 0​
VLD [36.1K]

For this case we must solve the following quadratic equation:

x ^ 2 + 2x-6 = 0

Where:

a = 1\\b = 2\\c = -6

The solution is given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting:

x = \frac {-2 \pm \sqrt {2 ^ 2-4 (1) (- 6)}} {2 (1)}\\x = \frac {-2 \pm \sqrt {4 + 24}} {2}\\x = \frac {-2 \pm \sqrt {28}} {2}\\x = \frac {-2 \pm \sqrt {2 ^ 2 * 7}} {2}\\x = \frac {-2 \pm2 \sqrt {7}} {2}\\x = -1 \pm \sqrt {7}

Thus, we have two roots:

x_ {1} = - 1+ \sqrt {7}\\x_ {2} = - 1- \sqrt {7}

ANswer:

x_ {1} = - 1+ \sqrt {7}\\x_ {2} = - 1- \sqrt {7}

8 0
3 years ago
What is the value of y?<br><br> 2<br> 5<br> 7<br> 8
swat32
I’m
confused by your question
6 0
2 years ago
Write an equation to show the best way to estimate 208 ÷ 7 using compatible numbers
Korvikt [17]

Answer:

210 ÷7 = 30

Step-by-step explanation:

We can round the numbers to numbers that make the math easier

I will round 208 to 210

We know 21 divide by 7 is 3

210 ÷7 = 30

This is very close to the actual answer.

208÷7 = 29.71428571........

5 0
3 years ago
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