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3 years ago

Help please must show work 1, 2, 3, 4

Mathematics

2 answers:

My name is Ann [436]3 years ago

8 0

Those are the answers for 1-4. Tell me if I should do the others or not.

Levart [38]3 years ago

3 0

The answer to the question

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Find the slope and reduce.<br> P=(-2, -1) Q=(6,5)<br> Slope = [ ? ]

m_a_m_a [10]

Answer:

Slope=3/4

Step-by-step explanation:

1) Label all values with x1 y1, x2 y2

Then, plug jn each value into this equation:y2-y1/x2-x1

Remember that negative values will become positive when dealjng with a subtraction sign.

5-(-1)=5+1.

---------------= 6/8

6-(-2)=6+2

After getting 6/8, simplify by the gcf (2) to get 3/4

Answer:3/4

3 0

3 years ago

A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long

wel

Answer: 0.3m/s

Step-by-step explanation:

Height/ velocity

3m/12m per sec

Time= 0.25metres per seconds

To the nearest tenth, 0.3m per seconds

5 0

3 years ago

Can somebody tell me how to solve these kind of problems?

Ugo [173]

Answer: 918km^2

Step-by-step explanation:

$area(a): 1700km^2\\percentage(p): 5.75 = \frac{5.75}{100}=0.0575\\years(y): 8$

Let x be the new dimension of the area;

$x=a-(a*p*y)$

$x=(1700km^2)-(1700km^2*0.0575*8)\\x=1700km^2-782km^2\\x=918km^2$

6 0

3 years ago

Erica can paint her room 5 hours .If she had her friend Rachel help her , they can paint the room together in 3 hours .How long

LUCKY_DIMON [66]

Answer:

7 hours 30min

Step-by-step explanation:

Step one :

Given data

We are told that Erica can paint 1 room in 5hours

Her work rate is 1/5 room per hour

And also with the assistance of her friend they can paint 1 room in 3 hours

Hence their combined work rate is 1/3 room per hour

Step two

The combined work expression is

1/A+1/B=1/T

Where A=Erica's work rate

B=Rachael's work rate

T=combined work

1/5+1/B=1/3

1/B=1/3-1/5

1/B=5-3/15

1/B=2/15

B=15/2

B=7.5 hours

It will take Rachel 7 hours 30min to paint the room

4 0

3 years ago

I really need help! This is last minute and its 1 am. I'm tired so I'm going to leave it to you guys to solve my problems and pr

Illusion [34]

Answer:

<h2><u>question 1</u></h2>

$n^{2} - 20n -96 = 0$

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

in the form $ax^{2} +bx +c = 0$

= $x^{2} +12x - 48$

make use of the formula :

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

replace values to make 2 equations :

1. $\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1}$ = 3.17

2. $\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1}$ = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

<u />

<h2><u>Question 4 </u></h2>

in the form $ax^{2} +bx +c = 0$

this becomes $5b^{2} -20b-18-7$

= $5b^{2} -20b-25$

can simplify by 5

= $b^{2} -4b-5 =0\\$

use product and sum method

product = -5

sum = -4

numbers needed (-5 , 1)

b-5 = 0

b + 1 = 0

hence <u>b = 5 and b = -1</u>

5 0

3 years ago

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