<span>The arc length by definition is given by:</span>
<span> S = R * theta</span>
<span> Where,</span>
<span> R: radio</span>
<span> Theta: central angle</span>
<span> Substituting values we have:</span>
<span> S = 10 * (3/2) pi</span>
<span> Rewriting we have:</span>
<span> S = 5 * (3) pi</span>
<span> S = 15pi</span>
<span> Answer:</span>
<span> The arc length is:</span>
<span> <span>S = 15pi</span></span>
Polynomials are not closed under division. When you divide polynomials it is possible to get quotients with negative exponents or with fractions that have exponents in the denominator, and neither of these could be included in polynomials.
Hello there.
6(8 - 2y) = 4y
To solve for this, we need to apply the Distributive Property to the left side of the equation. This property allows us to multiply the number outside of the parenthesis by all numbers inside of the parenthesis.
6(8 - 2y)
6(8) + 6(-2y)
48 - 12y
Now, let’s take a look at our equation.
-12y + 48 = 4y
To make things more simple, we’ll add 12y to both sides of the equation. This will cancel out -12y on the left side of the equation and will turn 4y on the right side of the equation into 16y.
Our new equation is:
16y = 48
Now all we need to do is divide both sides by 16 to solve for y.
16y / 16 = y
48 / 16 = 3
Our final answer and solution is:
Y = 3
I hope this helps!
9x - y = 15
2x + 8y = 28
Use the substitution method.
Solve for y in the first equation.
9x - y = 15
-y = 15 - 9x
y = -15 + 9x
Now plug in y into the second equation.
2x + 8(-15 + 9x) = 28
2x - 120 + 72x = 28
74x - 120 = 28
74x = 148
x = 2
Plug x back into the rewritten first equation.
y = -15 + 9(2)
y = -15 + 18
y = 3
x = 2, y = 3
Answer:
y = -5x + 20
Step-by-step explanation:
Lets start with the first given values for x and y
(2,10)
Lets try out the first equation
y = 5x + 4
y = 5(2) + 4
y = 14
This equation wouldn't work because the y value is not 10 when the x value is 2
y = 5x + 20
y = 5(2) + 20
y = 30
This equation doesn't work either
y = -5x + 20
y = -5(2) + 20
y = -10 + 20
y = 10
This would be the correct equation since your y value is 10 when the x value is 2
