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3 years ago

Please I really need help I know it is not A

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

6 0

The answer is D :DDDDDDDDDDD

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If 25 worker need 3 days to build a house how long will 10 worker need

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Answer:

3 x 10 = 30 man-days per house

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Dexter deposited 6,300 into a saving account that earns 2.60% simple interest per year. How much interest will she earn in 4 yea

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Answer:

Step-by-step explanation:

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3 years ago

A family spends 1/3 of its income for the mortgage and 1/6 of its income for food. What proportion of its income remains?

Aloiza [94]

Answer: 1/2

Step-by-step explanation:

1/3 = 2/6 so 2/6 + 1/6 = 3/6

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2 years ago

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Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

4 years ago

2x+3=x+x+3<br> Show your work

Nitella [24]

Step-by-step explanation:

2x+3=x+x+3

add the X's on the right side together.

2x+3=2x+3

subtract 2x from both sides

3=3

subtract 3 from both sides

0=0

the statement is true for any value of x

5 0

3 years ago