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Vsevolod [243]
3 years ago
7

6. Which value is a solution to the inequality? −3x −5 < −14

Mathematics
2 answers:
yan [13]3 years ago
8 0
First, add -5 to -14: 

-3x < -9 

Then, just divide!: 

x < 3
Hopefully that helped! :) 
kogti [31]3 years ago
7 0
The solution is x > 3
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4.) A recipe uses 1.75 cups of flour to make 24 cookies. How many cups of flour are needed to make 72 cookies? *
zaharov [31]

Answer:

5.47 cups of flour

Step-by-step explanation:

8 0
3 years ago
Question
KiRa [710]

Step-by-step explanation:

This problem bothers on the density of substances

Given data

Mass of substance m= 16kg

Volume of substance v = 2L

the equation that relates the volume. V. to the mass, m is the expression for density

ρ= mass/volume

Substituting our given data

ρ= 16/2= 8kg/L

Using the density calculated above we can get the volume liters, of 128kg of liquid

8= 128/v

v=128/8

v= 16L

The volume is 16L

The density of a substance is expressed as the mass per unit volume

3 0
3 years ago
Read 2 more answers
Alex and Morgan or ask to solve 2x-5=5x+7+3x X equal 5
monitta

Answer:

no solution?

Step-by-step explanation:

2(5)-5=5(5)+7+3(5)        <-- plug in 5

10−5=25+7+15

5=32+15

5=47

3 0
3 years ago
Complete the solution of the equation. find the value of y when x = -13
tresset_1 [31]
If x = -13, just plug -13 in for x in the equation, simplify, isolate the variable, and solve.
-4x + 5y = 12
-4(-13) + 5y = 12
-4 • -13 = 52
52 + 5y = 12
12 - 52 = -40
5y = -40
-40 / 5 = -8
y = -8

So when x is -13, y is -8.

Check the solution:
-4x + 5y = 12
-4(-13) + 5(-8) = 12
52 + (-40) = 12
52 - 40 = 12
12 = 12
It works, so this is correct.
3 0
4 years ago
Read 2 more answers
Factor <br> (a-2b) (3x-5y) + (2b-a)(x-y)
agasfer [191]

Answer:

8by + 2ax - 4bx - 4ay

Step-by-step explanation:

I assume you mean expand so:

(a - 2b)(3x - 5y) + (2b - a)(x - y)

3ax - 5ay - 6bx + 10by + 2bx - 2by - ax + ay

Now collect like terms:

2ax - 4ay - 4bx + 8by

This is your answer but in a better order:

8by + 2ax - 4bx - 4ay

6 0
2 years ago
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