Answer:
(a) 142 km trip requires 15.16 Liters of Gasoline
(b) The money spent is 69.34 euros or $87.37.
(c) The average speed of sprinter is 34.45 km/h.
(d) 4 lb of candy contains 0.559 kg of dietary fat.
Step-by-step explanation:
(a)
Given that;
Mileage = 22 mi/gal
Converting it to km/L
Mileage = (22 mi/gal)(1 gal/3.78 L)(1 km/0.6214 mi)
Mileage = 9.36 km/L
Now, the gasoline required for 142 km trip:
Gasoline Required = (Length of trip)/(Mileage)
Gasoline Required = (142 km)/(9.36 km/L)
<u>Gasoline Required = 15.16 L</u>
(b)
Given that;
Mileage = 30 mi/gal
Converting it to km/L
Mileage = (30 mi/gal)(1 gal/3.78 L)(1 km/0.6214 mi)
Mileage = 12.77 km/L
Now, the gasoline required for 142 km trip:
Gasoline Required = (Length of trip)/(Mileage)
Gasoline Required = (115 km/day)(7 days/week)/(12.77 km/L)
Gasoline Required = 63 L/week
Now, we find the cost:
Weekly Cost = (Gasoline Required)(Unit Cost)
Weekly Cost = (63 L/week)(1.1 euros/L)
<u>Weekly Cost = 69.34 euros/week = $87.37</u>
since, 1 euro = $1.26
(c)
Average Speed = (Distance Travelled)/(Time Taken)
Average Speed = 200 m/20.9 s
Average Speed = (9.57 m/s)(3600 s/1 h)(1 km/ 1000 m)
<u>Average Speed = 34.45 km/h</u>
(d)
22.7 g piece contains = 7 g dietary fat
(22.7 g)(1 lb/453.592 g) piece contains = (7 g)(1 kg/1000 g) dietary fat
0.05 lb piece contains = 0.007 kg dietary fat
1 lb piece contains = (0.007/0.05) kg dietary fat
4 lb piece contains = 4(0.007/0.05) kg dietary fat
<u>4 lb piece contains = 0.559 kg dietary fat</u>
