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meriva
3 years ago
12

Rewrite expression in the form k*z^n

Mathematics
1 answer:
Alik [6]3 years ago
6 0

Answer:

9z

Step-by-step explanation:

4th root of z = z^1/4

=> 3 * z^1/4

=> 3z^1/4

3z^1/4 * 3z^3/4

=> 3 x 3 x z^1/4 + 3/4

=> 9z^4/4

=> 9z^1

=> 9z

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Luis has saved $14 for a skateboard that costs $52. He can use the equation 14+m=52 to find how much more money m he needs. How
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Write the equation in standard form for the circle with center (0, -6) and radius 7.
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Step-by-step explanation:

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2 years ago
Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.
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Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

f(x) = \frac{x^2+4x+3}{x^2-x-2}

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial x^2-x-2

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

(x-2) (x + 1)

We do the same with the numerator

x^2+4x+3

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

(x+3)(x + 1)

Therefore

f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}

Note that \frac{(x+1)}{(x+1)}=1 only if x \neq -1

So since x = -1 is not included in the domain the function has a discontinuity in x = -1

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3 years ago
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