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2 years ago

2/17+3/7(3x−5)=−4 What is the solution?

1 answer:

8 0

2/17 + 3/7(3x - 5) = -4
2/17 + 9/7x - 15/7 = -4...multiply by LCD of 119 to get rid of fractions
14 + 153x - 255 = - 476
-241 + 153x = -476
153x = -476 + 241
153x = - 235
x = -235/153

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Round 7.04 to the nearest tenths

Strike441 [17]

Answer:

it's 10 I think lol.....

4 0

3 years ago

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If 8(x) is the inverse of f(x) and f(x) = 4x + 12 what is g(x) ?

kompoz [17]

Answer:

(y-12)/4

Step-by-step explanation:

If g(x) is the inverse of f(x)

and f(x) = 4x + 12

f⁻¹(x) = g(x)

let f(x) be represented as y

f(x) = y

y = 4x + 12

subtract 12 from both sides

y-12= 4x

divide both sides by 4

(y-12)/4 = x

so f ⁻¹ (y)= (y-12)/4 so g(x) = (x-12)/4

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2 years ago

The number of marriage licenses issued by Clark County Nevada, the county where Las Vegas is located, has been

REY [17]

The number of marriage licenses were issued in 2003 is 21586.

According to the statement

we have to find the number of marriage licenses were issued in 2003

and the given equation is y=3.405x^2-17674x+21533000

And in this equation x represent the time

And Y represent the number of marriage certificate issued.

So, in given equation

y=3.405x^2-17674x+21533000

we fill the value of X and find the value of Y means tne number of marriage license is issued in 2003

We know that X = 3 from 2000 to 2003

Then put X=3 in the given equation.

Then

This is the equation (1) represent the change

y=3.405(3)^2-17674(3)+21533000 -(1)

y = 30.645+53022+21533000

y = 21586052.645

On nearest hundred the value becomes 21586.

So, The number of marriage licenses were issued in 2003 is 21586.

Learn more about NUMBERS here brainly.com/question/1770447

DISCLAIMER: The question was incomplete. please find the full content below.

QUESTION:

According to the model, how many marriage licenses were issued in 2003? Round your answer to the nearest hundred.

The number of marriage licenses issued by Clark county Nevada, the county where Las Vegas is located, has been decreasing since the year 2000. This can be modeled by y=3.405x^2-17674x+21533000 where x is the year and y is the number of marriage licenses issued.

#SPJ1

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1 year ago

Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Upper H 0: pequals0.6 versus U

kow [346]

Answer:

Step-by-step explanation:

From the given information:

The null and the alternative hypothesis can be well written as:

$H_o:P=0.6$

$H_1:P>0.6$

Given that:

n = 200

x = 135

Alpha ∝ = 0.05 level of significance

Then;

⇒ $n \times p\times (1-P)$

= 200 × 0.6 × (1 -0.6)

= 200 × 0.6 × 0.4

= 48 ≥ 10

The sample proportion $\hat P = \dfrac{x}{n}$

$= \dfrac{135}{200}$

= 0.675

The test statistics $Z = \dfrac{\hat P - P}{\sqrt{ \dfrac{P(1-P)}{n} }}$

$Z = \dfrac{0.675 - 0.6}{\sqrt{ \dfrac{0.6 \times 0.4}{200} }}$

$Z = \dfrac{0.075}{\sqrt{ \dfrac{0.24}{200} }}$

Z = 2.165

The P-value = P(Z > 2.165)

= 1 - P(Z < 2.165)

From the z tables

= 1 - 0.9848

= 0.0152

Reject the null hypothesis since P-Value is lesser than alpha. ( i.e. 0.0152 < 0.05).

Thus, there is enough evidence to conclude that the value of the population proportion is greater than 0.6

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3 years ago

Is the following a function?

saw5 [17]

Answer:

yes

Step-by-step explanation:

For the relation to be a function, there must only be one corresponding value of y (range) for any value of x in the domain, that is a one-to- one relationship

This graph displays this feature and is a function.

5 0

3 years ago

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