BRO I DONT KNOW ANSWER EAST OR WEAST MY ANSWER IS BEST
A right triangle has one leg with unknown length, the other leg with length of 5 m, and the hypotenuse with length 13 times sqrt 5 m.
We can use the Pythagorean formula to find the other leg of the right triangle.
a²+b²=c²
Where a and b are the legs of the triangle and c is the hypotenuse.
According to the given problem,
one leg: a= 5m and hypotenuse: c=13√5 m.
So, we can plug in these values in the above equation to get the value of unknown side:b. Hence,
5²+b²=(13√5)²
25 + b² = 13²*(√5)²
25 + b² = 169* 5
25+ b² = 845
25 + b² - 25 = 845 - 25
b² = 820
b =√ 820
b = √(4*205)
b = √4 *√205
b = 2√205
b= 2* 14.32
b = 28.64
So, b= 28.6 (Rounded to one decimal place)
Hence, the exact length of the unknown leg is 2√205m or 28.6 m (approximately).
Let x represent the amount to be added. The total amount of tin will be
15%·20 + 10%·x = 12%·(20+x)
(15%-12%)·20 = (12%-10%)·x
3%·20/2% = x
30 = x
30 pounds of 10% tin must be added to get a 12% mixture.
190-15=x
I believe?
I THINK THIS IS THE ANSWER
The first is in the form y=Mx+b where m is the slope and b is the y-intercept. Start at 600 on the y-axis and graph with a slope of six. The second is in the same form but the y-intercept is 0, so start at the origin and graph with a slope of 8. The last is in the form y=b+mx, so start at 1300 and graph with a slope of 3. Remember, slope is rise/run or (change in y)/(change in x). Since the domain and range start at 0 these graphs will only be in the first quadrant with an x limit of 650 and a y limit of 1500.
