Exercise 1:
exponential decay:
The function is given by:
y = A (b) ^ ((1/3) * t)
Where,
A = 600
We look for b:
(480/600) * (100) = 80%
b = 0.8
Substituting:
y = 600 * (0.8) ^ ((1/3) * t)
We check for t = 6
y = 600 * (0.8) ^ ((1/3) * 6)
y = 384
Answer:
exponential decay:
y = 600 * (0.8) ^ ((1/3) * t)
Exercise 2:
linear:
The function is given by:
y = ax + b
Where,
a = -60 / 2 = -30
b = 400
Substituting we have:
y = -30 * x + 400
We check for x = 4
y = -30 * 4 + 400
y = 280
Answer:
linear:
y = -30 * x + 400
Exercise 3:
exponential growth:
The function is given by:
y = A (b) ^ ((1/3) * t)
Where,
A = 512
We look for b:
(768/512) * (100) = 150%
b = 1.5
Substituting:
y = 512 * (1.5) ^ ((1/2) * t)
We check for t = 4
y = 512 * (1.5) ^ ((1/2) * 4)
y = 1152
Answer:
exponential growth:
y = 512 * (1.5) ^ ((1/2) * t)
Step-by-step explanation:
8/3 cups of sugar is needed to make 16 cookies.
For 90 cookies, we will need 8/3 * 90/16 = 15 cups of sugar.
Since you can 4 pieces from 1 foot, you multiply 4 by 5 and you get 20 pieces.
Using a system of equations, it is found that one large jar holds 6 ounces and one small jar holds 4 ounces.
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
- Variable l: Weight that a large jar holds.
- Variable s: Weight that a small jar holds.
One large jar and five small jars can hold 26 ounces of jam, hence:
l + 5s = 26, which is the first equation in matrix form.
Then:
l = 26 - 5s.
One large jar minus one small jar can hold 2 ounces of jam, hence:
l - s = 2, which is the second equation in matrix form:
Then:
l = 2 + s = 26 - 5s
2 + s = 26 - 5s
6s = 24
s = 4.
l = 26 - 5s = 6.
More can be learned about a system of equations at brainly.com/question/24342899
#SPJ1
Answer:
x = 4
Step-by-step explanation:
AB + BC = AC,
2x + x + 5 = 17,
3x = 12,
x = 4
