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monitta
3 years ago
5

Inset < or > to make a true statement. -2.9 __ 3.8

Mathematics
1 answer:
nordsb [41]3 years ago
5 0
< makes it a true statement
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In how many arrangements can 3 boys and 4 girls stand in a row such that no two boys are together?
Sophie [7]

Answer: 1440

Step-by-step explanation:

To arrange 3 boys and 4 girls such that no two boys are together.

Since boys should be arranged between the girls.

So first arrange the girls.

Assume that the girls are placed, then there will be 5 spaces left for 3 boys.

The number of combinations to fill these places = ^5C_3=\dfrac{5!}{3!2!}=\dfrac{5\times4}{2}=10

Also, 3 boys can arrange themselves in 3! =3 x 2 x 1 = 6 ways

4 girls can arrange themselves in 4! = 4x 3 x 2 x 1 = 24 ways

Then, the total number of arrangements = 10 x 6 x 24 = 1440

Hence, the required number of arrangements = 1440

5 0
2 years ago
Input, x 4 8 12 16 20 output y 21 37 53 69 85 what is the equation
BigorU [14]

Answer:

The equation is y = 4x + 5

Step-by-step explanation:

To find the equation to this table, pick two ordered pairs and use the slope formula to find the slope. For this we'll use (4, 21) and (8, 37).

m(slope) = (y2 - y1)/(x2 - x1)

m = (37 - 21)(8 - 4)

m = 16/4

m = 4

Now we can use that slope along with any point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 21 = 4(x - 4)

y - 21 = 4x - 16

y = 4x + 5

3 0
3 years ago
 Evaluate the polynomial function p (x) = 2x4 - 3x2 + x - 1 to find p (-1).
Alisiya [41]
p(x)=2x^4-3x^2+x-1\\\\&#10;Substitude\ p=-1\ into\ equation\\\\&#10;p(-1)=2x^4-3x^2+x-1=2*(-1)^4-3(-1)^2-1-1=\\2*1-3*1-2=2-3-2=-3\\Answer\ p(-1)=-3
7 0
3 years ago
How to solve 1-(-8)- 12/-3
Fudgin [204]

Answer:

ok so the answer is 13

Step-by-step explanation:

to solve you..

PEMDAS

PLEASE EXUSE MY DEAR AUNT SALLY

1-(-8)-12/-3

1-(-8)+4

1+8+4

9+4

13

!

HOPE THIS HELPED YA

4 0
3 years ago
Find the sum of the first 42 terms of the following series, to the nearest
balandron [24]

Answer:

Step-by-step explanation:

Find the sum of the first 42 terms of the following series, to the nearest integer.

2,7,12

Solution

The sum is given by  

SUM_n=n/2*(a_1+a_n)

a_n=a_1+(n-1)d

a_1=2,   n=42,     d=5

The 42nd term is therefore given by  

a_42=2+(42-1)5=207

SUM_42=42/2*(2+207)=21*209=4389

The sum of the first 42 terms of the series, therefore, is 4389

5 0
2 years ago
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