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Mariulka [41]
3 years ago
15

deb has a board that measures 5 feet in length how many 1/4 foot long pieces can deb cut from the board?

Mathematics
2 answers:
Julli [10]3 years ago
5 0
Since you can 4 pieces from 1 foot, you multiply 4 by 5 and you get 20 pieces.
Verdich [7]3 years ago
3 0
1/4 = .25  It takes 4 forths to make 1 whole. And there are 5 wholes. so 4x5=20.
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Does the point (0, 0) satisfy the equation y = 9x?
miskamm [114]

Answer:

yes it does

Step-by-step explanation:

because the equation y=9x does not have a y-intercept (all slopes come in the form y=mx+b -- it can be written differently though) and since there is no 'b' that means the y-intercept is 0. So whenever there is no y-intercept, the slope starts at 0.

6 0
2 years ago
What is (6,2) rotation 270
nignag [31]

Given:

The point is (6,2).

To find:

The image of given point after rotation of 270 degrees.

Solution:

Let the given point be P(6,2).

Rotation of 270 degrees means the figure is rotated 270 degrees counterclockwise about the origin. So, the rule of rotation is

(x,y)\to (y,-x)

Using this rule, we get

P(6,2)\to P'(2,-6)

Therefore, the image of given point is (2,-6).

3 0
3 years ago
What’s the vertical asymptote of the equation f(x)=log3(x-5)
ICE Princess25 [194]

Answer:The line x=5

Step-by-step explanation:

Asymptote of a function means the straight line closest to some part of the function which tends to ∞  or -∞. We know that ln x or log x has asymptote x=0. Here , the function is f(x) = log 3(x-5), so, the vertical asymptote will be the line x =5.

7 0
3 years ago
The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term
Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be 1, 5, and 25.

The sum of the first seven terms of the geometric sequence would be 127.

Step-by-step explanation:

<h3>1.</h3>

Let d denote the common difference of the arithmetic sequence.

Let a_1 denote the first term of the arithmetic sequence. The expression for the nth term of this sequence (where n\! is a positive whole number) would be (a_1 + (n - 1)\, d).

The question states that the first term of this arithmetic sequence is a_1 = 1. Hence:

  • The third term of this arithmetic sequence would be a_1 + (3 - 1)\, d = 1 + 2\, d.
  • The thirteenth term of would be a_1 + (13 - 1)\, d = 1 + 12\, d.

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let r denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d.

Ratio between the third term and the second term of the geometric sequence:

\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}.

Both (1 + 2\, d) and \left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right) are expressions for r, the common ratio of this geometric sequence. Hence, equate these two expressions and solve for d, the common difference of this arithmetic sequence.

\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}.

(1 + 2\, d)^{2} = 1 + 12\, d.

d = 2.

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be 1, (1 + (3 - 1) \times 2) = 5, and (1 + (13 - 1) \times 2) = 25, respectively.

These three terms (1, 5, and 25, respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be r = 25 /5 = 5.

<h3>2.</h3>

Let a_1 and r denote the first term and the common ratio of a geometric sequence. The sum of the first n terms would be:

\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}.

For the geometric sequence in this question, a_1 = 1 and r = 25 / 5 = 5.

Hence, the sum of the first n = 7 terms of this geometric sequence would be:

\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}.

7 0
2 years ago
Coffee beans are packaged in 50 kg cartons with an allowable error of 0.7% What is the acceptable weight range for a carton of c
goldfiish [28.3K]
0.35, you multiply 50 times 0.7%
6 0
3 years ago
Read 2 more answers
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