3 years ago

PLEASE HELP ASAP!!! (ii only)

1 answer:

6 0

The equation of the tangent line can be found using slope formula and fact that slope = dy/dx.

$\frac{dy}{dx} = \frac{y - y_0}{x - x_0}$

where (x0,y0) is point A ---> (0,-1)

Then rearrange equation into slope-intercept form:
$y = \frac{dy}{dx}(x - 0) -1$

Finally sub in x=0 into dy/dx to get slope at the point (0,-1)

$y = 3x -1$

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Expanding and Adding Expressions Use the expansion shown to simplify the expression. One-half (3 x minus two-thirds y) + 3 (Star

Lisa [10]

Answer:

$3x+\frac{7}{6}y$

Step-by-step explanation:

To simplify the expression, we first open the parenthesis, then we collect all the like terms. Lastly we simplify the like terms to its simplest form. Given that:

$\frac{1}{2}(3x-\frac{2}{3} y)+3(\frac{x}{2}+\frac{1}{2}y )\\\\Firstly, we\ expand\ the\ parenthesis:\\\\=\frac{1}{2}(3x)-\frac{1}{2}(\frac{2}{3} y)+3\frac{x}{2}+3(\frac{1}{2} y)\\$

$=\frac{3}{2}x-\frac{1}{3}y +\frac{3}{2}x+\frac{3}{2} y\\\\ Collecting\ like\ terms:\\\\=\frac{3}{2}x+\frac{3}{2}x-\frac{1}{3}y+\frac{3}{2}y\\\\Adding \ terms:\\\\=3x +\frac{7}{6}y$