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Ierofanga [76]
3 years ago
7

What are two ratios that are equivalent to 2:9

Mathematics
1 answer:
Lena [83]3 years ago
8 0

Answer:

4:18 and 8:27

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The game commission observes the fish population in a stream and notices that the number of trout increases by a factor of 1.5 e
just olya [345]

Answer:

A - f(t)=80(1.5)^t

B - Graph given below

C - Number of trouts in 5th week are 607.2

D - Population of trouts will exceed 500 on the 5th week.

Step-by-step explanation:

We are given that,

The number of trout increases by a factor of 1.5 each week and the initial population of the trout is observed to be 80.

Part A: So, the explicit formula representing the situation is,

f(t)=80(1.5)^t, where f(t) represents the population of trouts after 't' weeks.

Part B: The graph of the function can be seen below.

It can be seen that the function is an exponential function.

Part C: It is required to find the number of trouts in the 5th week.

So, we have,

f(5)=80(1.5)^5

i.e. f(5)=80\times 7.59

i.e. f(5) = 607.2

Thus, the number of trouts in 5th week are 607.2

Part D: We are given that the trout population exceeds 500.

It is required to find the week in which this happens.

So, we have,

50

i.e. (1.5)^t>\frac{500}{80}

i.e. (1.5)^t>6.25

i.e. t\log 1.5>\log 6.25

i.e. t\times 0.1761>0.7959

i.e. t>\frac{0.7959}{0.1761}

i.e. t > 4.5

As, t represents the number of weeks. So, to nearest whole, t = 5.

Thus, the population of trouts will exceed 500 on the 5th week.

7 0
3 years ago
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