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Maurinko [17]
3 years ago
11

Tamika went hiking with her friends. The beginning of -1 feet. The highest elevation on hiking path is 100 feet. What is the dif

ference in the two elevations?
Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
5 0
<h2>Answer:</h2>

The difference in the two elevations is:

                         101 feet.

<h2>Step-by-step explanation:</h2>

It is given that:

 Tamika went for hiking with her friends and the beginning of the hiking was: -1 feet

and the highest elevation on hiking path is 100 feet.

This means that the difference in the two elevations are:

Highest elevation -  Beginning elevation of hiking

=   100- (-1)

= 100+1

= 101 feet

const2013 [10]3 years ago
4 0

hello!

so the difference is 101 and here is why!

you want to minus -1 from 100

100 - (-1)

but because it is a double negative it will become addition

100 + 1

so the difference is 101 feet

i hope this helped :)

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STEP 4: Calculate the Standard deviation

\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ \sum ^{}_{}(x_i-\bar{x})^2\Rightarrow\text{Sum of squares of differences} \\ \Rightarrow10332.7225+657.9225+18591.3225+982.8225+2740.52251+9731.8225+3522.4225+18319.6225+2878.3225 \\ +8163.1225+1417.5225+3925.0225+1321.3225+386.1225+5677.6225+2953.9225+3800.7225 \\ +3209.2225+2565.4225+10537.0225 \\ \text{Sum}\Rightarrow108974.0275 \\  \\ S\tan dard\text{ deviation}=\sqrt[]{\frac{111714.55}{20-1}}=\sqrt[]{\frac{111714.55}{19}} \\ \Rightarrow\sqrt[]{5879.713158}=76.67928767 \\  \\ S\tan dard\text{ deviation}\approx76.68 \end{gathered}

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