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Andrej [43]
3 years ago
14

Kevin went to see his favorite sports team play his car can go 320 miles on one lank of gas. If he used 20% of a full tank of ga

s, how many miles did he travel? ​
Mathematics
2 answers:
Oxana [17]3 years ago
7 0

Answer:

64 miles

Step-by-step explanation:

If he used 20% of the gas, he can go 20% of the miles

20% of 320 miles

.20 * 320

64 miles

Stells [14]3 years ago
3 0

Answer:

\huge\boxed{\sf 64\ miles}

Step-by-step explanation:

A total tank travels to 320 miles

Let the miles be x

<u>He used 20% of the full tank</u>

=> 20% of the full tank = x

=> \frac{20}{100} * 320 = x

=> 2 * 32 = x

=> x = 64 miles

So, He traveled 64 miles in 20% of the tank.

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The line 6x - 2y = 12 goes through -6 on the y-axis and 2 on the x-axis ie through (0, -6) and (2, 0)
The line will be solid and shaded above (towards the origin)

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Here is my selection.
(0, 0) is in the solution set. 6 x 0 - 2 x 0 = 0 which is less than 12
(5, 0) is not in the solution set. 6 x 5 - 2 x 0 = 30 which is greater than 12
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3 years ago
How do I solve these measurement problems?
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Answer:

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P=44.6

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3 0
3 years ago
When 15 is subtracted from 3 times a number the result is -32. what is the number?
Vilka [71]

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Two people are standing on opposite sides of a hill. Person A makes an angle of elevation of 65° with the top of the hill and pe
8090 [49]

Answer:

Option 3. 71 ft. is the distance between B and top of the hill.

Step-by-step explanation:

Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.

It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.

We have to find the distance of B from the top of the hill.

Now from ΔACO tan 65 = \frac{h}{45-x} = 2.14

h=2.14(45-x)

From ΔBCO tan80 = \frac{h}{x} = 5.67

h = 5.67x

Now h = 5.67x = 2.14(45-x)

5.67x = 96.3 - 2.14x

2.14x + 5.67x = 96.3

7.81x = 96.3

x = 96.3/7.81 = 12.33 ft

Therefore cos80 = \frac{x}{OB}

0.174 = \frac{12.33}{OB}

OB = \frac{12.33}{.174}=70.86=71ft.

Therefore 71 ft is the distance between B and the top of the hill.

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3 years ago
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