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wel
3 years ago
9

Monique made several batches of soup for a potluck supper. Each batch required 3\4 0f a pound of potatoes, and she used a total

of 6 1/2 pounds of
potatoes. Solve the division problem.

What is 13/2 ÷ 3/4
Mathematics
2 answers:
Hoochie [10]3 years ago
6 0

Answer:

D. 8 2/3

Step-by-step explanation: HOPES THIS HELPS!

Tju [1.3M]3 years ago
4 0

Answer:

It’s 8 2/3

Step-by-step explanation:

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Use the formula you found in the previous question to find the degree of angle B if angle A = 35 and angle C = 90.
jok3333 [9.3K]

Answer: 55

Step-by-step explanation:

90+35=125

180 is the total degrees of an angle so 180-125= 55

6 0
3 years ago
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In a bakery, the number of buns delivered is a function of the number of boxes packed. What is the domain of this function? The
Elenna [48]
Your domain would include only positive integers, or zero. The value of the buns cannot be negative; in other words, you cannot have a negative number of buns. The same principle applies to boxes. However, you can have zero buns or zero boxes. Hope this helps. 
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3 years ago
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Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x
BaLLatris [955]

Answer:

The area of the region is 25,351 units^2.

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em>f<em> is a continuous function on </em>[a,b]<em>, then</em>

                                   \int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) |  {_a^b}

where F is an antiderivative of f.

A function F is an antiderivative of the function f if

                                                    F^{'}(x)=f(x)

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x + 15 and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx

\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2

3 0
3 years ago
PLEASE HELP FAST!!!
Rus_ich [418]

\\ \sf\longmapsto 3s-5+2s+25=170

\\ \sf\longmapsto 5s+20=170

\\ \sf\longmapsto 5s=170-20

\\ \sf\longmapsto 5s=150

\\ \sf\longmapsto s=30

  • m<GHZ=3(30)-5=90-5=85
  • m<ZHI=2(30)+25=60+25=85
4 0
2 years ago
Which of these is the algebraic expression for "eight less than some number?"
kipiarov [429]
B-8 would be the answer. This is because we are saying you have 8 less than something. So no matter what something is, we are taking away 8 from it. Since our something is unknown, we use our variable 'b' in its place, and subtract 8, giving us b-8.<span />
8 0
3 years ago
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