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JulsSmile [24]
2 years ago
12

FIRST CORRECT ANSWER GETS BRAINLIEST

Mathematics
2 answers:
Andrej [43]2 years ago
4 0
The answer is 5s - 10t + 7
k0ka [10]2 years ago
4 0
Following the order of operations (PEMDAS):

Step 1: simplify what’s inside the parentheses. Since we don’t know either variable s or t, we can’t simplify any further from what it already is.

Step 2: distribute the 5 to each of the terms inside the parentheses. This gets you (5s - 10t)

Step 3: arrange your final answer:
7 + 5s - 10t

You can’t simplify any more unless you know one the the variables so you are left with this.
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3 years ago
Based on a​ survey, assume that 43​% of consumers are comfortable having drones deliver their purchases. Suppose we want to find
svlad2 [7]

Answer:

The probability of getting two consumers comfortable with drones is 0.3424.

Step-by-step explanation:

The probability that a consumer is comfortable having drones deliver their purchases is, <em>p</em> = 0.43.

A random sample of <em>n</em> = 5 consumers are selected, and exactly <em>x</em> = 2 of them are comfortable with the drones.

To compute the probability of getting two consumers comfortable with drones followed by three consumers not​ comfortable, we will use the Binomial distribution instead of the multiplication rule to find the probability.

This is because in this case we need to compute the number of possible combinations of two consumers who are comfortable with drones.

So, <em>X</em> = number of consumers comfortable with drones, follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.43.

Compute the probability of getting two consumers comfortable with drones as follows:

P(X=x)={5\choose x}\ 0.43^{x}\ (1-0.43)^{5-x};\ x=0,1,2,3...

P(X=2)={5\choose 2}\ 0.43^{2}\ (1-0.43)^{5-2}

               =10\times 0.1849\times 0.185193\\=0.342421857\\\approx 0.3424

Thus, the probability of getting two consumers comfortable with drones is 0.3424.

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3 years ago
LeShawn runs 1,448 meters per minute, what is his average meters per hour ?
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