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ANTONII [103]
3 years ago
5

The height of the pyramid in the diagram is three times the radius of the cone. The base area of the pyramid is the same as the

base area of the cone. What is the expression for the volume of the pyramid in terms of the radius r of the cone?
Mathematics
2 answers:
jeyben [28]3 years ago
8 0
It is said that the area of the base of the pyramid and that of the cone are equal. In this case, the are a of the square base is s^2 while the area of circle is pi r^2. Hence, s = sqrt pi * r. The volume of the pyramid has a formula of 1/3 bh. h is equal to 3r. Hence, V =  1/3 bh = 1/3 pi r^2 * 3r =  pi r^3. 
nataly862011 [7]3 years ago
7 0

Answer:

1/3 pi r^2 * 3r =  pi r^3.

Step-by-step explanation:

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In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. But what about on the Moon? If an as
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Answer:

The acceleration due to gravity on the moon is 1.642 m/s².      

Step-by-step explanation:

Given : In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. If an astronaut on the surface of the moon swings a 1-meter long pendulum, and it has a period of 4.9 seconds.

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Solution :

The pendulum formula is T=2\pi \sqrt{\frac{L}{g}}

where, T is the time period,

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We have to find the value of g acceleration due to gravity on the moon.

The formula became,

g'=(\frac{2\pi}{T})^2\times L

Substitute T=4.9 seconds , L= 1 m

g'=(\frac{2\times 3.14}{4.9})^2\times 1

g'=(\frac{6.28}{4.9})^2

g'=\frac{39.4384}{24.01}

g'=1.642

The acceleration due to gravity on the moon is 1.642 m/s².

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3 years ago
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