Instead of having to write multiple pieces of code for different outcomes, you can use an elseif statement and make your code easier to read and easier to understand.
Answer:
Option a. int max = aList.get(0); for (int count = 1; count < aList.size(); count++) { if (aList.get(count) > max) { max = aList.get(count); } }
is the correct code snippet.
Explanation:
Following is given the explanation for the code snippet to find largest value in an integer array list aList.
- From the array list aList, very first element having index 0 will be stored in the variable max (having data type int).
- By using for starting from count =1 to count = size of array (aList), we will compare each element of the array with first element of the array.
- If any of the checked element get greater from the first element, it gets replaced in the variable max and the count is increased by 1 so that the next element may be checked.
- When the loop will end, the variable max will have the greatest value from the array aList.
i hope it will help you!
A complete program with the method ShowCar:
import java.util.Scanner; // header file
public class ShowChar
{
public static void main(String[] args)
{
String lnOfText;
int i;
Scanner input = new Scanner(System.in);
System.out.print("Enter a line of text:");
lnOfText = input.nextLine();
System.out.print(" Enter your index: ");
i = input.nextInt();
show_Char(lnOfText,i);
}
public static void show_Char(String str_a, int i)
{
System.out.print(str_a.charAt(i));
}
}
In this program, both the inputs ie. a sentence or line of text as well as the index position is obtained. A method is written to find the string at that particular position. Finally the method prints that character at the particular index.
