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Novosadov [1.4K]
3 years ago
6

A nursery has 10 tree seedlings to give out at 2 workshops. It wants to give out a minimum of 2 seedlings at each workshop. How

many different ways can the nursery give out seedlings?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0

We are given total 10 tree seedlings.

Number of workshops = 2.

Here order doesn't matters.

<em>When order doesn't matters we apply combination.</em>

We know formula of combination:

C(n,r) = \frac{n!}{r!(n-r)!}

For the given situation, we have

n=10 and r=2.

Plugging values in formula, we get

\frac{10!}{2!(10-8)!}  = \frac{10\times 9\times8!}{2!8!}

\frac{10 \times 9}{2} = \frac{90}{2} =45

<h3>Therefore, 45 different ways can the nursery give out seedlings.</h3>
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<u>Pre-Algebra</u>

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<u>Step 1: Identify</u>

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<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [PT]:                                                                                                (x + 3)² + x² = (√117)²
  2. Expand [FOIL]:                                                                                                 x² + 6x + 9 + x² = (√117)²
  3. Combine like terms:                                                                                       2x² + 6x + 9 = (√117)²
  4. Exponents:                                                                                                      2x² + 6x + 9 = 117
  5. [SPE] Subtract 117 on both sides:                                                                    2x² + 6x - 108 = 0
  6. Factor out GCF:                                                                                               2(x² + 3x - 54) = 0
  7. [DPE] Divide 2 on both sides:                                                                         x² + 3x - 54 = 0
  8. Factor Quadratic:                                                                                            (x - 6)(x + 9) = 0
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Since we are dealing with positive values, we can disregard the negative root.

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