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3 years ago

41 out of 50 women surveyed liked perfume. what percentage of women did not like perfume

Mathematics

1 answer:

SpyIntel [72]3 years ago

5 0

Answer:

82%

Step-by-step explanation:

because you have to divide 41 by 50 then,move the decimal 2 places to the right.

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In a random sample of n1 = 162 males, there are x1 = 63 people that have blue eyes. In a random sample of n2 = 333 females, ther

sesenic [268]

Answer:

z = 2.1784 > 1.96,

Reject the null hypothesis

Step-by-step explanation:

For the males:

n1 = 162, x1 = 63

P1 = x 1/ n1 = 0.3889

For the Females:

n2 = 333,

x2 = 97

P 2 = x2/n2

= 0.2913

P 1= P2 Null hypothesis

P 1 is not equal to P 2 alternative hypothesis

Pooled proportion:

P= (x1 + x2) /( n1+ n2)

= (63 + 97) / (162 + 333)= 0.3232

Test statistics :

Z= (p1 - p2) /√p(1-p)× (1/n1 + 1/n2)

0.3889- 0.2913 / √0.3232 × 0.6768 × (1/162 +1/333)

=2.1784

c) Critical value :

Two tailed critical value, z critical = Norm.S .INV (0.05/2) = 1.960

Reject H o if z < -1.96 or if z > 1.96

d) Decision:

z = 2.1784 > 1.96,

Reject the null hypothesis

7 0

3 years ago

An oil exploration firm is formed with enough capital to finance ten explorations. The probabil- ity of a particular exploration

tensa zangetsu [6.8K]

Answer:

μ = 1 The firm expects that one oil exploration will be successful.

v(x)= 0.9

Step-by-step explanation:

The first step is to define the random variable x as:

x: number of oil explorations being succesful

Then x can be take this values:

x = 0 , x =1 ... x =10

x is a binomially distributed random variable with parameters.

p = 0.1 and n=10

And the mean or the expected value of x is:

μ = E(x) = np

Then μ = 10*0.1 = 1

And the variance of x is:

V(x) = np(1-p)

V(x) = 10(0.1)(1-0.1)= 0.9

6 0

2 years ago

Find the distance between the points L and D. A)-2 B)0 C)1 D)2

Alisiya [41]

Answer:

C) 1

there is only one space between L and D

8 0

3 years ago

United Blood Services is a blood bank that serves more than 500 hospitals in 18 states. According to their website, a person wit

Anna11 [10]

Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

43% of people have type O blood

This means that $P(A) = 0.43$

15% of people have Rh- factor

This means that $P(B) = 0.15$

52% of people have type O or Rh- factor.

This means that $P(A \cup B) = 0.52$

a. Find the probability that a person has both type O blood and the Rh- factor.

This is

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

With what we have

$P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06$

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

1 - 0.06 = 0.94

0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

6 0

2 years ago

Find the point on the line y = 2x +1 that is closest to the point (5, 2).

ELEN [110]

I believe that it's (1,3)
(tip: with these problems, try to use desmos.com)

7 0

3 years ago