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katovenus [111]
3 years ago
13

41 out of 50 women surveyed liked perfume. what percentage of women did not like perfume

Mathematics
1 answer:
SpyIntel [72]3 years ago
5 0

Answer:

82%

Step-by-step explanation:

because you have to divide 41 by 50 then,move the decimal 2 places to the right.

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Yes because 6×6 is 36 and 9×4 is 36.
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tigry1 [53]
The  answer of t he  trapezoid  area  problem is  112.
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You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Otrada [13]

Answer:

Please check the explanation.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

7 0
3 years ago
A hypothesis test is to be performed for a population proportion. For the given sample data and null hypothesis, compute the val
liberstina [14]

Answer:

The correct option is a

Step-by-step explanation:

From the question we are told that

    The sample size is n =  415

    The sample proportion is  \r p  = 0.49

Now

     The null hypothesis is  H_o  :  p = 0.3

     The alternative hypothesis is H_a  :  p \ne 0.3

The test statistics is mathematically evaluated as

      t  =  \frac{\r p -  p  }{ \frac{\sqrt{ p (1- p )} }{n} }

substituting values

      t  =  \frac{0.49 -  0.3  }{ \sqrt{ \frac{0.3 (1- 0.3 ) }{415} }}

     t  = 8.446

     

8 0
4 years ago
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melamori03 [73]
Tyler used the Distributive Property
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