Choose the vector has a magnitude of √2 and a direction of θ = 135°.
2 answers:
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Answer:
Step-by-step explanation:
Let the equation of the perpendicular line is,
y = mx + b
where m = slope of the line
b = y-intercept
From the graph, slope of the line passing through (0, -1) and (3, 1),
m' =
m' =
m' =
To get the slope (m) of this line we will use the property of perpendicular lines,
m × m' = (-1)
m × = -1
m =
Equation of the perpendicular line will be,
x-intercept of the line is (-3) therefore, point on the line is (-3, 0)
0 =
b =
Equation of the line will be,