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masya89 [10]
2 years ago
10

A classmate stated, "A concave polygon be can be regular because it can have all sides congruent." Is this student's claim valid

?
Why or why not?
Mathematics
1 answer:
Novosadov [1.4K]2 years ago
7 0

Answer:

No.

Step-by-step explanation:

A regular polygon has all sides and angles congruent. This is not possible with a concave polygon. If the sides are congruent in a concave polygon the angles  are not congruent.

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In triangle abc, the length of side and is 10 inches and the length of side be is 17 inches . Which of the following could be th
earnstyle [38]

Answer:

a^2=b^2+c^2.

a^2=10^2+17^2.

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5 0
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Which equation represents the graph of y= cosx reflected across the x-axis then shifted vertically down by 2 units?
Phoenix [80]

Answer:

  y = -cos(x) -2

Step-by-step explanation:

Multiplying the function value by -1 reflects it across the x-axis. Adding -2 to the function value shifts it down by two units.

reflected: y = -cos(x)

then shifted: y = -cos(x) -2

6 0
3 years ago
HELP ON THIS PROBLEM!!<br><br> Solve the following 0deg&lt; x&lt; 360deg: cos x= cos 2x
blsea [12.9K]

Answer:

x=0^\circ,120^\circ,240^\circ,360^\circ

Step-by-step explanation:

<u>Use identities to set the equation up as a quadratic</u>

\cos x=\cos 2x;\:0^\circ \leq x \leq 360^\circ\\\\\cos x=2\cos^2 x-1\\\\0=2\cos^2 x-\cos x-1

<u>Make the substitution u=cos(x) and solve the quadratic</u>

<u />0=2u^2-u-1\\\\0=(2u+1)(u-1)

\displaystyle 0=2u+1\\\\0=2\cos x+1\\\\-1=2\cos x\\\\-\frac{1}{2}=\cos x\\\\120^\circ,240^\circ=x

0=u-1\\\\0=\cos x-1\\\\1=\cos x\\\\0^\circ,360^\circ=x

Hence, x=0^\circ,120^\circ,240^\circ,360^\circ

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Answer:

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Step-by-step explanation:

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2 years ago
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