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Musya8 [376]
4 years ago
7

Which statement best relates an empirical formula with a molecular formula?

Chemistry
1 answer:
Gemiola [76]4 years ago
7 0
Molecular formulas can be determined from empirical formulas. Molecular formula is a chemical formula that shows the kind of atoms and the number of each atom. An empirical formula is a formula that gives the proportions of the elements present in a certain compound.
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Why is there more black moths than white ones​
vlada-n [284]

Answer:

Uhhhh life?

Explanation:

5 0
3 years ago
Choose the best classification of the reactions C6H12O6 (g) + 6O2 yields 6CO2 + 6H2O
marta [7]
Combustion reaction because it produces water and carbon dioxide
6 0
3 years ago
How many moles of hydrochloric acid are required to produce .40 moles of hydrogen gas?
mash [69]

Answer:

0.80 Moles of Hydrochloric Acid would be required to produce 0.40 Moles of hydrogen gas due to the equation ratios

Explanation:

How many moles of hydrochloric acid are required to produce .40 moles of hydrogen gas?

Hydrochloric acid = HCl

Hydrogen gas = H2

H = 1+

Cl = 1-

HCL = H2 + Cl2

2HCl = H2 + Cl2

2:1:1

0.80 = 0.40 + 0.40

4 0
3 years ago
What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i
UNO [17]

Answer:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)

The net equation is then:

Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-

Actual cathode half-equation:

Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)

Actual net reaction:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

6 0
3 years ago
Describe the orbital notation and electron configuration notation to describe the placement of all of the electrons in an atom o
andriy [413]
The arrangement of the electrons on the orbitals is governed by the principles of quantum energy. To be able to draw the correct electronic configuration of an element, they should follow these three principles.

1. Aufbau's Principle. The electrons of an element should be filled up from the highest energy level. You can use the periodic table as a guide for this. In decreasing order, the energy of the orbitals are 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d and 7p. Each 'box' of these orbital must be filled with two electrons from 1s before moving on to the next.

2. Hund's rule. This states that you must fill all boxes of one orbital with one electron first. For example, 2p has 3 boxes. You fill one electron for each box first before going back to fill it to two electrons if there are still excess.

3. Pauli's Exclusion Principle. This states that no electrons of the same element should have the same quantum numbers. To achieve this, the two electrons in each box should have opposite spins, one facing up, and the other facing down.

Using these three rules, you will be able to draw the electronic configuration of Fluorine with 9 electrons as shown in the picture.

7 0
4 years ago
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