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natka813 [3]
3 years ago
11

If 13.5 L of nitrogen gas reacts with 17.8 L of hydrogen gas at STP, according to the following reaction, what mass of ammonia w

ould be produced? N2 + 3 H2 --> 2 NH3 Report your answer with proper significant figures, only a number answer is required, no units needed for this form.
Chemistry
2 answers:
Shalnov [3]3 years ago
6 0

Answer: N5 + H4 and then do 13.5 * 17.8 then solve so 240.3 divided by 9

Your answer is 26.7  Pretty sure

Explanation: (study)

ser-zykov [4K]3 years ago
4 0

Answer:

Work is all on the paper

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Answer:

- 10.555 kJ/mol.

Explanation:

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  • Calculating ∆S°rxn:

∵  ∆S°rxn = ∑∆S°products - ∑∆S°reactants

<em>∴ ∆S°rxn = (2 x ∆S° NOCl) - (1 x ∆S° Cl₂) - (2 x ∆S° NO) </em>= (2 x 261.6 J/mol.K) - (1 x 223.0 J/mol.K) - (2 x 210.65 J/mol.K) =<em> - 121.1 J/mol.K. = - 0.1211 kJ/mol.K.</em>

<em></em>

  • Calculating ∆G°rxn:

∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.

<em>∴ ∆G°rxn = ∆H°rxn - T∆S°rxn </em>= (- 77.16 kJ/mol) - (550 K)(- 0.1211 kJ/mol.K) = <em>- 10.555 kJ/mol.</em>

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