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Verdich [7]
3 years ago
5

Show example for problem. 4(d+2) = what?

Mathematics
1 answer:
Lynna [10]3 years ago
8 0

Answer:

4d+8

Step-by-step explanation:

mutiply it in

4*d=4d

2*4=8


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Write the ratio statement as a fraction and reduce to lowest te<br> 20 pounds to 45 ounces
Alenkasestr [34]

Answer:

5/9

Step-by-step explanation:

fraction: 20/45

lcd of 25 and 45 is 5

25 ÷ 5 = 5

45 ÷ 5 = 9

therefore; 5/9

5 0
3 years ago
Can someone pleasee help me out I don’t understand ?
galina1969 [7]

Answer:

Step-by-step explanation:

It's easier to start by putting this into fraction form.

  1 1/4

Then put the fraction into a decimal.

  1 1/4 is the same as 1.25

After that, turn the decimal into a percentage.

  1.25 turns into 125%

6 0
3 years ago
I need help on this plz ​
Shalnov [3]

Answer:

x = 3

Step-by-step explanation:

You can use cross multiply.

8x = 6 x 4

8x = 24

x = 3

7 0
3 years ago
Read 2 more answers
Malika's rectangular garden is enclosed with 24 m of fencing.
olasank [31]
The greatest possible area with a fixed length of fencing (perimeter) is a circle.

Circumference = 2 pi x radius = 24 m
Radius = (24 m) / (2 pi) = 12 m / pi

Area of a circle = pi x radius squared = (pi) x (12 m / pi)^2 = 144 / pi = 45.837 square meters.
=====================================
The rectangle with the greatest possible area for a fixed perimeter is the square.

Each side of the square = 24 / 4 = 6 meters

Area of a square = (side) squared = 36 square meters 
=====================================
There is no 'least possible' area.  The longer and skinnier you make it,
the less area it will have.

Here are some examples. Each one has 24 m of fencing:

5 m x 7 m = 35 square meters
4 x 8 = 32 square meters
3 x 9 = 27 square meters
2 x 10 = 20 square meters
1 x 11 = 11 square meters
0.5 x 11.5 = 5.75 square meters
0.1 x 11.9 = 1.19 square meters
1 centimeter x 11.99 meters = 0.1199 square meters
1 millimeter by 11.999 meters = 0.011999 square meters

The longer and skinnier the garden is, the less area it has.

 








3 0
4 years ago
A bookstore can purchase several calculators for a total cost of $120. If each calculators cost $1 less, the bookstore could pur
Tresset [83]
x-number\ of\ calculators\ sold\ in\ regular\ price\\\\&#10;y-\ \ first\ price\\\\&#10;(y-1)\ \ -second\ price\\\\x=\frac{120}{y}\\&#10;x+10=\frac{120}{y-1}\\\\Substitude\  x=\frac{120}{y}\ into\ the\ second\\\\\&#10;\frac{120}{y}+10=\frac{120}{y-1}\ \ |-\frac{120}{y-1}-10\\\\&#10;\frac{120}{y}-\frac{120}{y-1}=-10\\\\Make\ a\ common\ denominator\\\\&#10;\frac{120(y-1)}{y(y-1)}-\frac{120y}{(y-1)y}=-10&#10;\frac{120y-120)}{y(y-1)}-\frac{120y}{(y-1)y}=-10\\\\&#10;\frac{120y-120-120y}{y(y-1)}=-10<u />Assumptions:\\y \neq 0\ \ \ and\ \ y \neq 1\\\\ \frac{-120}{y(y-1)}=-10\ \ \ | *y(y-1) \\\\&#10;-120=-10y(y-1)\\\\&#10;-120=-10y^2+10y\\\\&#10;10y^2-10y-120=0\ \ \ |:10\\\\&#10;y^2-y-12=0\\\\Factor\ equation\\\\ y^2+3y-4y-12=0\\\\&#10;(y-4)(y+3)=0\\\\Solutions:\ \ y=4\ \ and\ \ y=-3
8 0
4 years ago
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