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SVEN [57.7K]
3 years ago
5

What is 3498 divided by 7.Explain how you got this answer and why you think its reasonable

Mathematics
1 answer:
Mashcka [7]3 years ago
8 0
Here is your answer click the file

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W is the midpoint of VX and Z is the midpoint of VY . If XY=p and WZ=p–30, what is WZ?
juin [17]

\large{ \tt{❃ \: EXPLANATION}} :

  • You'll have to know : Mid-point theorem states that A straight line segment joining the mid-points of any two triangle is parallel to the third side and it is equal to half of the length of the third side.

  • We're provided : XY = p , WZ = p - 30 & we're asked to find out the value of WZ. For that , firstly we have to find out the value of p.

\large{ \tt{❁ \: LET'S \: START }: }

  • Set up an equation & solve for p :

\large{ \bf{☄ \: p  - 30 =  \frac{1}{2}  p }}

\large{ \tt{↦ \frac{1}{2} p = p - 30}}

\large{ \tt{↦ \frac{1}{2} p - p =  - 30}}

\large{ \tt{↦ \frac{p - 2p}{2} =  - 30 }}

\large{ \tt{↦p - 2p =  - 60}}

\large{ \tt{ ↦ \: - p =  - 60}}

\large{ \tt{↦p = 60}}

  • The value of p is 60

\large{ \tt{❇ \: REPLACING \: VALUE}} :

\large{ \tt{↬ \: wz = p - 30 =  60 - 30 =   \boxed{\boxed{ \tt{30 }} }✔}}

  • Hence , WZ = 30 .

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7 0
3 years ago
2/5 of a bag of soil fills 1/3 of a container, Is 1 bag of soil enough to fill 1 container?
natka813 [3]

Answer:

No.

Step-by-step explanation:

Let's find out if 1 bag of soil is enough to fill 1 container.

<u>Given:</u>

2/5 of a bag fills 1/3s of a containter.

With the given, multiplying 2/5 by 2.5 represents one. Multiply 1/3 by 2.5 aswell.

<u>Products:</u>

1, and 2.5/3 or 5/6

1 bag can fill 5/6 of a container.

Therefore, 1 bag can't fill 1 container.

7 0
2 years ago
Please I need you guys help​
borishaifa [10]

Plz mark me as brainliest if this helped :)

6 0
3 years ago
Read 2 more answers
What is the common ratio of the sequence?<br><br> -2, 6, -18, 54,...
navik [9.2K]
The common ratio is the multiplicity of -3

hope this helps
8 0
3 years ago
Read 2 more answers
A map provided by an engineering firm has a scale of 1 inch to 2000 feet. If the distance from the starting point for a pipeline
8090 [49]

Answer:

27,000 feet

Step-by-step explanation:

Let x be the actual length of the pipeline, in feet.

Set up the following proportion:

\displaystyle\\\frac{1}{2,000}=\frac{13.5}{x}

Cross-multiplying yields x=13.5\cdot 2,000=\boxed{27,000\text{ ft}}

7 0
2 years ago
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