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kumpel [21]
3 years ago
6

Boxes of sticky hands popsicles are 4.50. The supermarket is offering a 30% off coupon. What is the price with the coupon?

Mathematics
2 answers:
blondinia [14]3 years ago
4 0
1.35=x that's ur answer
ArbitrLikvidat [17]3 years ago
3 0
Included in your weekly circular should be free coupons, so coupons are free (disregarding the price you have to pay to live around the area)


if you want to know how much discount the coupon give you then

4.5*3/10=1.35
takes off $1.35

proportion method

30/100=x/4.5
3/10=x/4.5
cross multiply or ties both sides by 10*4.5
3*4.5=10x
13.5=10x
divide both sides by 10
1.35=x


discount of $1.35 (coupon saves you $1.35)
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Select the correct answer. 3 Twenty-seven minus 2 of a number (X) is not more than 36. What is the number? N O A. x > 42 OB.
e-lub [12.9K]

Answer:

the answer should be A.

Step-by-step explanation:

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3 0
3 years ago
X 11 -5 2 16 Y 6 -13 10 13 Is this relation a function? YES OR NO​
Tasya [4]

Answer:

this is a function I beleive

hope this helps

5 0
3 years ago
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Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of
jarptica [38.1K]

Answer:

The "probability that a given score is less than negative 0.84" is  \\ P(z.

Step-by-step explanation:

From the question, we have:

  • The random variable is <em>normally distributed</em> according to a <em>standard normal distribution</em>, that is, a normal distribution with \\ \mu = 0 and \\ \sigma = 1.
  • We are provided with a <em>z-score</em> of -0.84 or \\ z = -0.84.

Preliminaries

A z-score is a standardized value, i.e., one that we can obtain using the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

Where

  • <em>x</em> is the <em>raw value</em> coming from a normal distribution that we want to standardize.
  • And we already know that \\ \mu and \\ \sigma are the mean and the standard deviation, respectively, of the <em>normal distribution</em>.

A <em>z-score</em> represents the <em>distance</em> from \\ \mu in <em>standard deviations</em> units. When the value for z is <em>negative</em>, it "tells us" that the raw score is <em>below</em> \\ \mu. Conversely, when the z-score is <em>positive</em>, the standardized raw score, <em>x</em>, is <em>above</em> the mean, \\ \mu.

Solving the question

We already know that \\ z = -0.84 or that the standardized value for a raw score, <em>x</em>, is <em>below</em> \\ \mu in <em>0.84 standard deviations</em>.

The values for probabilities of the <em>standard normal distribution</em> are tabulated in the <em>standard normal table, </em>which is available in Statistics books or on the Internet and is generally in <em>cumulative probabilities</em> from <em>negative infinity</em>, - \\ \infty, to the z-score of interest.

Well, to solve the question, we need to consult the <em>standard normal table </em>for \\ z = -0.84. For this:

  • Find the <em>cumulative standard normal table.</em>
  • In the first column of the table, use -0.8 as an entry.
  • Then, using the first row of the table, find -0.04 (which determines the second decimal place for the z-score.)
  • The intersection of these two numbers "gives us" the cumulative probability for z or \\ P(z.

Therefore, we obtain \\ P(z for this z-score, or a slightly more than 20% (20.045%) for the "probability that a given score is less than negative 0.84".

This represent the area under the <em>standard normal distribution</em>, \\ N(0,1), at the <em>left</em> of <em>z = -0.84</em>.

To "draw a sketch of the region", we need to draw a normal distribution <em>(symmetrical bell-shaped distribution)</em>, with mean that equals 0 at the middle of the distribution, \\ \mu = 0, and a standard deviation that equals 1, \\ \sigma = 1.

Then, divide the abscissas axis (horizontal axis) into <em>equal parts</em> of <em>one standard deviation</em> from the mean to the left (negative z-scores), and from the mean to the right (positive z-scores).  

Find the place where z = -0.84 (i.e, below the mean and near to negative one standard deviation, \\ -\sigma, from it). All the area to the left of this value must be shaded because it represents \\ P(z and that is it.

The below graph shows the shaded area (in blue) for \\ P(z for \\ N(0,1).

7 0
3 years ago
Can you help givie full info thanks
liubo4ka [24]

Answer:

13

Step-by-step explanation:

Using long division, you can multiply each given value by 100 to eliminate the decimals:

2.08x100=208

0.16x100=16

OR (calculator method)

2.08÷0.16=13

You must divide the amount of food per cat by the total amount of food available to determine how many cats can be fed.  This division can be done using a calculator.

OR

5 0
2 years ago
Read 2 more answers
Jen’s goal is to run a total of 22 miles in five days. The table below shows her log for the number of miles she ran on Monday,
Ronch [10]

Answer: 5.875 miles run on Friday to reach her goal by Jen

Step-by-step explanation:

Since we have given that

Part of distance covered on Monday by Jen is given by

4\frac{3}{4}=\frac{19}{4}

Part of distance covered on Tuesday by Jen is given by

5\frac{1}{8}\\\\=\frac{41}{8}

Part of distance covered on Wednesday by Jen is given by

0

Part of distance covered on Thursday by Jen is given by

6\frac{1}{4}\\\\=\frac{25}{4}

Total part of distance covered in these four days by Jen is given by

\frac{19}{4}+\frac{41}{8}+0+\frac{25}{4}\\\\=\frac{38+41+0+50}{8}\\\\=\frac{129}{8}=16.125\ miles

Remaining part of distance will be covered on Friday to reach her goal which is given by

22-16.125=5.875\ miles

Hence, 5.875 miles run on Friday to reach her goal by Jen.


5 0
3 years ago
Read 2 more answers
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