the value of -4*2 is -8 jdjdjdjdhdhdjdjdjdhdh
Given:
The system of equations:


To find:
The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.
Solution:
We have,
...(i)
...(ii)
The coefficient of x in (i) and (ii) are 1 and
respectively.
To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.
It means, we have to convert
into -1. It is possible if we multiply the equation (ii) by -5.
On multiplying equation (ii) by -5, we get
...(iii)
On adding (i) and (iii), we get

Here, x is eliminated.
Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.
Answer:
Hi how are you doing today Jasmine
Answer: 3 1/3
Step-by-step explanation:
Turned into mixed numbers: -7/3 + 17/3
Multiply all the numbers by 3: -7 * 3 = -21
17 * 3 = 51
3 * 3 = 9
-21 + 51 = 30
30/9
30/9 = 3 1/3
Answer:
The value of rate per annum is R = 12.5 %
Step-by-step explanation:
Principal amount = 576
Interest = 153
Amount after 2 years = 576 + 153 = 729
We know that
![A = P [1 + \frac{R}{100} ] ^{T}](https://tex.z-dn.net/?f=A%20%3D%20P%20%5B1%20%2B%20%5Cfrac%7BR%7D%7B100%7D%20%5D%20%5E%7BT%7D)
Put all the values in above equation
![729 = 576 [1 + \frac{R}{100} ]^{2}](https://tex.z-dn.net/?f=729%20%3D%20576%20%5B1%20%2B%20%5Cfrac%7BR%7D%7B100%7D%20%5D%5E%7B2%7D)

R = 12.5 %
This is the value of rate per annum.