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3 years ago

Find the length of a to the nearest tenth using the Pythagorean theorem

Mathematics

1 answer:

Leona [35]3 years ago

8 0

Answer:

Ab^2 = CA^2 + BC^2

8^2 = 6^2 + a^2

64 = 36 + a^2

64-36 = a^2

28 = a^2

square root of 28 = square root of a^2

5 ,29 = a

5 = a

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Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 2323 Pennies 55 Dimes 2020 Nic

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The answer is "0.081"

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I need helping answering 15. I need to create a table and graph the function.

Alekssandra [29.7K]

ANSWER and EXPLANATION

We want to order the functions from widest to narrowest:

$\begin{gathered} y=3x^2 \\ y=2x^2 \\ y=4x^2 \end{gathered}$

To do this, we have to plot the graphs of the functions by using a table of values.

Let us find the values of the functions for values of x = -2, 0, 2

For the first function:

$\begin{gathered} y=3x^2 \\ \Rightarrow x=-2: \\ y=3(-2)^2=3*4 \\ y=12 \\ \Rightarrow x=0: \\ y=3(0)^2=3*0 \\ y=0 \\ \Rightarrow x=2: \\ y=3(2)^2=3*4 \\ y=12 \end{gathered}$

Hence, its table is:

For the second function:

$\begin{gathered} y=2x^2 \\ \Rightarrow x=-2: \\ y=2(-2)^2=2*4 \\ y=8 \\ \Rightarrow x=0: \\ y=2(0)^2=2*0 \\ y=0 \\ \Rightarrow x=2: \\ y=2(2)^2=2*4 \\ y=8 \end{gathered}$

Hence, its table is:

For the third function:

$\begin{gathered} y=4x^2 \\ \Rightarrow x=-2: \\ y=4\left(-2\right)^2=4*4 \\ y=16 \\ \Rightarrow x=0: \\ y=4(0)^2=4*0 \\ y=0 \\ \Rightarrow x=2: \\ y=4(2)^2=4*4 \\ y=16 \end{gathered}$

Hence, its table is:

Now, let us plot the graphs of the functions:

Therefore, from the graph, we see that the order of the functions from widest to narrowest is:

$y=2x^2;y=3x^2;y=4x^2$

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