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2 years ago

6

Company A charges $107 and allows unlimited mileage.

1 answer:

skad [1K]2 years ago

7 0

Answer:

At mile 3 company A will start charging less.

Step-by-step explanation:

I came to this conclusion by realizing that no matter what company A will always charge $107 so, in theory all we needed to do was get company eight to $108. So having this mind set I created the equation, 65 + .70x . I continuously kept on changing what was in x until the price was just above Company A's. And the number that got me there was 3.

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5x^2-26x+5 factor the trinomial

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The factored form for this question is (5x-1)(x-5)

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3 years ago

An equation that defines y as a function of x is given. Solve for y in terms of x, and replace y with the function notation f(x)

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3 years ago

$140 for 18ft squared=?????

andrew11 [14]

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3 years ago

Read 2 more answers

Find 2 numbers a and b such that (a-b)^2 < (a+b)(a-b)< (a+b)^2 Find two numbes a and b such that this is not true

Svet_ta [14]

Suppose for the moment that the inequality holds for all $a,b$ :

$(a-b)^2$

Expanding everything gives

$a^2-2ab+b^2$

$\implies-ab$

In particular, the inequality says that $-ab$ for any choice of $a,b$ . But if $a$ and $b>0$ , then $-ab>0$ while $ab$ .

So one possible choice of $a,b$ could be $a=-1$ and $b=1$ . Then we get

$(-1-1)^2=4$

$(-1+1)(-1-1)=2$

$(-1+1)^2=0$

but clearly it's not true that $4$ .

8 0

2 years ago

The playing life of a Sunshine radio is normally distributed with mean LaTeX: \muμ = 600 hours and standard deviation LaTeX: \si

Hitman42 [59]

Answer:

The probability that a radio selected at random will last from 600 to 700 hours is 0.3413

Step-by-step explanation:

The playing life of a Sunshine radio is normally distributed

Mean = $\mu = 600 hours$

Standard deviation = $\sigma = 100 hours$

We are supposed to find the probability that a radio selected at random will last from 600 to 700 hours i.e.P(600<x<700)

Formula: $Z= \frac{x-\mu}{\sigma}$

At x = 600

$Z= \frac{600-600}{100}$

Z=0

$P(X$

At x = 700

$Z= \frac{700-600}{100}$

Z=1

$P(X$

$P(600$

Hence the probability that a radio selected at random will last from 600 to 700 hours is 0.3413

8 0

3 years ago